Python 多个客户端聊天不起作用



当我运行main和client的py文件时,没有显示错误,但没有显示发送消息的输入。如何修复?

main.py结果-->正在等待。。。并连接192.168.1.26 58767

clients.py结果-->无

这是主要的.py

import threading
import socket
server = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
server.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
host="192.168.1.26"
port=1111
threadcount=0
server.bind((host,port))
print("Waiting...")
server.listen(3)

def clients(connection):
connection.send(str.encode("welcomen"))
while True:
data=connection.recv(2048)
reply="server says" + data.decode("utf-8")
if not data:
break
connection.sendall(str.encode(reply))
connection.close()
while True:
client,adress=server.accept()
print("connected"+ str(adress[0]) + " " + str(adress[1]))
threading.Thread(target=clients,args=(client,))
threadcount+=1
server.close()

这是客户.py

import socket
client_socket=socket.socket()
host="192.168.1.26"
port=1111
client_socket.connect((host,port))
response=client_socket.recv(1024)
print("hello")
while True:
input=input("say")
client_socket.send(str.encode(input))
Response=client_socket.recv(1024)
print(Response.decode("utf-8"))
client_socket.close()

看起来您的线程从未真正启动过。一种解决方案是定义一个类,在run例程中实现线程逻辑。类应该继承threading.Thread。然后,您可以简单地将类初始化为对象,并调用其start例程。请尝试以下原始服务器代码的变体。

import threading
import socket
server = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
server.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
host="192.168.1.26"
port=1111
threadcount=0
server.bind((host,port))
print("Waiting...")
server.listen(3)
class ServerThread(threading.Thread):
def __init__(self, threadsocket):
threading.Thread.__init__(self)
self.threadsocket = threadsocket
def run(self):
self.threadsocket.send(str.encode("welcomen"))
while True:
data=self.threadsocket.recv(2048)
reply="server says" + data.decode("utf-8")
print(reply)
if not data:
break
self.threadsocket.sendall(str.encode(reply))
self.threadsocket.close()
while True:
client,adress=server.accept()
print("connected"+ str(adress[0]) + " " + str(adress[1]))
thread = ServerThread(client)
thread.start()
threadcount+=1
server.close()

就客户端而言,正如我在评论中提到的,您不应该使用input作为变量名来存储input函数的结果。改为类似data的内容。

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