如何从字典中的列表中获取变量

Question

我有这样的数据；

{"result": [{"name": "Mil", "age": 21, "id": 1}, {"name": "Jen", "age": 23, "id": 2}, {"name": "Rosa", "age": 26, "id": 3}]}

我如何才能从Python中这样的数据中只得到每个人的"年龄"值？

Answer 1

您可以访问以下年龄：

d = {"result": [{"name": "Mil", "age": 21, "id": 1}, {"name": "Jen", "age": 23, "id": 2}, {"name": "Rosa", "age": 26, "id": 3}]}
ages = [res["age"] for res in d["result"]]  # [21, 23, 26]

事实上，d["result"]是一个dicts列表。因此，在更扩展的形式中，它与相同

d = {"result": [{"name": "Mil", "age": 21, "id": 1}, {"name": "Jen", "age": 23, "id": 2}, {"name": "Rosa", "age": 26, "id": 3}]}
results = d["result"]  # a list
ages = []
for res in results:
age = res["age"]
ages.append(age)
print(ages)  # [21, 23, 26]

Answer 2

您可以使用以下代码：

dic={"result": [{"name": "Mil", "age": 21, "id": 1}, {"name": "Jen", "age": 23, "id": 2}, {"name": "Rosa", "age": 26, "id": 3}]}
lst = dic["result"]
age_lst =[]
for i in range(len(lst)):
age =lst[i]["age"]
age_lst = [age]+age_lst
print(age_lst)