如何使用rusqlite在sqlite数据库中插入和获取日期



我有一个带有NaiveDate字段的结构,我想将此字段插入到表中。这是我的全部代码

use chrono::naive::NaiveDate; 
use rusqlite::{params, Connection, Result};
#[derive(Debug)]
struct Person {
id: i32,
name: String,
date: NaiveDate,
}
fn main()->Result<()>{
let date_str = "2020-04-12";
let naive_date = NaiveDate::parse_from_str(date_str, "%Y-%m-%d").unwrap();
let me = Person {
id: 0,
name: "Steven".to_string(),
date: naive_date,
};
println!("{:?}",me);

let conn = Connection::open_in_memory()?;


conn.execute(
"CREATE TABLE person (
id              INTEGER PRIMARY KEY,
name            TEXT NOT NULL,
date            TEXT
)",
[],
)?;

conn.execute(
"INSERT INTO person (name, date) VALUES (?1, ?2)",
params![me.name, me.date],
)?;

let mut stmt = conn.prepare("SELECT id, name, date FROM person")?;
let person_iter = stmt.query_map([], |row| {
Ok(Person {
id: row.get(0)?,
name: row.get(1)?,
date: row.get(2)?,
})
})?;
for person in person_iter {
println!("Found person {:?}", person.unwrap());
}

Ok(())
}

但它给出了这两个错误

|   the trait `FromSql` is not implemented for `NaiveDate`
|   the trait `ToSql` is not implemented for `NaiveDate`

cargo.toml

chrono = "0.4.19"
rusqlite = "0.25.0"

您必须使用额外的chrono特性进行编译,才能为chrono类型实现FromSqlToSql特性。

将Cargo.toml中的申报更改为

chrono = "0.4.19"
rusqlite = { version = "0.25.0", features = ["chrono"] }

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