我正在做一个蚂蚁模拟，我需要存储所有的信息素(int值(
以下是它的工作原理：
- 当蚂蚁进入睡眠时，它会沉积10个信息素。(已完成(
- 每个蜱虫的信息素值都会降低一，并且不会低于0
我需要一些东西来做最后一件事
这是我的代码：
# world is the map on a 1000x1000 array of 0 at the start
def evaporate():
for x in range(len(world)):
for y in range(len(world[0])):
if world[x][y] > 0:
world[x][y] -= 1
我认为有更好的方法来存储映射值，但我找不到有效的方法
如果你不能使用任何库，那会更好，因为我想看看我的程序能做什么，但如果它更高效或更容易，那没关系
如果有错别字，告诉我我会改正的。(英语不是我的主要语言(
谢谢你抽出时间。
一个1000乘1000的世界有1.000.000个瓦片。一个是你的基地，几个是蚂蚁，有些里面有信息素
不存储完整的地图，只存储数据所在的位置。你可以用一本以(x，y(为关键字的字典。
由于信息素水平为10代表蚂蚁，你可以这样做：
class ant():
import random
# movement delta in 8 directions
_delta_move = [(dx,dy) for dx in range(-1,2) for dy in range(-1,2)]
def __init__(self, x, y, maxage = 5):
self.__x = x
self.__y = y
self.age = maxage
def getPos(self):
return (self.__x, self.__y)
def kill(self):
self.age = 0
def random_move(self):
# every move reduces ants age, when 0 it dies
self.age -= 1
if self.age > 0:
d = random.choice(ant._delta_move)
self.__x += d[0]
self.__y += d[1]
return self.getPos()
return None # dead
创建蚂蚁列表和地图并传播移动：
mapsize = 10
# helper
def print_map(m):
"""prints the map, if a pheromon level is 10 the ant is in this field"""
for y in range(mapsize):
print(" #",end="")
for x in range(mapsize):
value = m.get( (x,y), " ")
if value == 10:
value = "a"
elif value == 0:
value = " "
print(value, end="")
print()
# list of ants
ants = [ ant(5, 5, 6) for _ in range(5 )]
# initial map, 10 pheromones is max per field
ant_map = { a.getPos():10 for a in ants}
while (ants):
print_map(ant_map)
input("Enter for next round")
# decay pheromones
done = [] # store keys to delete, avoid changing dict while iterating
for key,value in ant_map.items():
if value > 0:
ant_map[key] -= 1
else:
done.append(key)
for k in done:
del ant_map[k]
# remove dead ants
ants = [a for a in ants if a.age > 0]
# move ants and add new pheromones
for a in ants:
# move ant
new_pos = a.random_move()
if new_pos and 0 <= new_pos[0] < mapsize and 0 <= new_pos[1] < mapsize:
ant_map[new_pos] = 10
else:
a.kill()
print_map(ant_map)
输出：
#
#
#
#
#
# a
#
#
#
#
Enter for next round
#
#
#
#
# a a
# aa
#
#
#
#
Enter for next round
#
#
#
# a
# a 9a
# 9a
# a
#
#
#
Enter for next round
#
#
#
# 9aa
# a9a89
# 89
# a9
#
#
#
Enter for next round
#
#
# a a
# 8a9
# a8978
# 7a
# 98
#
#
#
Enter for next round
#
#
# 9a9
# a 7a8
# 97a67
# 6a
# 87
#
#
#
Enter for next round
#
#
# 898
# 9 697
# 86956
# 59
# 76
#
#
#
Enter for next round
#
#
# 787
# 8 586
# 75845
# 48
# 65
#
#
#
Enter for next round
#
#
# 676
# 7 475
# 64734
# 37
# 54
#
#
#
Enter for next round
#
#
# 565
# 6 364
# 53623
# 26
# 43
#
#
#
Enter for next round
#
#
# 454
# 5 253
# 42512
# 15
# 32
#
#
#
Enter for next round
#
#
# 343
# 4 142
# 314 1
# 4
# 21
#
#
#
Enter for next round
#
#
# 232
# 3 31
# 2 3
# 3
# 1
#
#
#
Enter for next round
#
#
# 121
# 2 2
# 1 2
# 2
#
#
#
#
Enter for next round
#
#
# 1
# 1 1
# 1
# 1
#
#
#
#
试试这个：
import numpy as np # <-- for efficient storage
import matplotlib.pyplot as plt # <-- for visualization
# Initialize a random map with values from 0 to 10.
pheromone_map = np.random.randint(low=0, high=11, size=(1000, 1000))
# Visualize the pheromones disappearing
for i in range(10):
# clip removes any negative value from the array that had 1 subtracted from it
pheromone_map = np.clip(pheromone_map - 1, a_min=0, a_max=11)
# Shows how the pheromones disappear
fig, ax = plt.subplots()
ax.imshow(pheromone_map)