获取静态函数以返回async值

Question

我希望静态ES6方法只返回一个值，而不是promise。这就是我要做的。

export default class Member {
static existingMember() {
var _existingMember;
// DB.findExistingMember() -> returns a promise
DB.findExistingMember().then(member => {
_existingMember = member
})
return _existingMember
}
}
// in mocha test
describe('some test', function () => {
const member = Member.existingMember()
it('has access to member', function() => {
// I want member to be available here instead of having to do member.then()
console.log(member)
foo.someFunction(member)
bar.someFunction(member)
})
})

Answer 1

您可以在Member.existingMember函数上使用wait，将member用作正常变量

export default class Member {
static existingMember() {
return DB.findExistingMember();
}
}
// in mocha test
describe('some test', function ()  {
it('has access to member', async function () {
const member = await Member.existingMember()
console.log(member)
foo.someFunction(member)
bar.someFunction(member)
})
})