如何对对象数组进行文件管理，并根据特定值只返回一个对象

Question

我有一个包含两个计划对象的数组：

[ { "id": "price_aehdw424i7rxyeqiquedwuy", 
    "name": "Monthly Plan", 
    "price": 2900, 
    "interval": "month", 
    "currency": "usd",
  }, 
 { "id": "price_46r34dgqn4d7w4fdw3476r323", 
   "name": "Yearly Plan", 
   "price": 29900, 
   "interval": "year", 
   "currency": "usd",
 } ]

我想做的是使用一个值(customerPlanId(通过将其与plan.id匹配来找到正确的计划，然后返回正确的计划。如下所示：

{ "id": "price_aehdw424i7rxyeqiquedwuy", 
    "name": "Monthly Plan", 
    "price": 2900, 
    "interval": "month", 
    "currency": "usd",
  }

我知道我可以映射到计划并筛选出正确的计划，但我如何单独返回正确的计划对象？

Answer 1

解决方案

您可以使用"；Array.find"；方法

示例

Stacklitz Snippet

Answer 2

const plan =  [ { "id": "price_aehdw424i7rxyeqiquedwuy", 
    "name": "Monthly Plan", 
    "price": 2900, 
    "interval": "month", 
    "currency": "usd",
  }, 
 { "id": "price_46r34dgqn4d7w4fdw3476r323", 
   "name": "Yearly Plan", 
   "price": 29900, 
   "interval": "year", 
   "currency": "usd",
 } ]
const filtered  = plan.find((x)=>x.id === yourId)

Answer 3

let obj = [ { "id": "price_aehdw424i7rxyeqiquedwuy", 
    "name": "Monthly Plan", 
    "price": 2900, 
    "interval": "month", 
    "currency": "usd",
  }, 
 { "id": "price_46r34dgqn4d7w4fdw3476r323", 
   "name": "Yearly Plan", 
   "price": 29900, 
   "interval": "year", 
   "currency": "usd",
 } ];
 
 search_id = "price_aehdw424i7rxyeqiquedwuy";
 let filtr = obj.filter(function(element){
     if(element.id==search_id) return element
 });
 
 
console.log (filtr.length?filtr[0]:'Not Found');