如何将字符串字典转换为某些值为列表的字典

Question

我有这样一个字典的字符串表示：

s = "{'indexed': {'date-parts': [[2020, 9, 29]], 'date-time': '2020-09-29T19:03:40Z', 'timestamp': 1601406220500}}"

如果我使用json.loads(s)转换为dict，我会得到一个错误，因为date-parts的值是list:

---------------------------------------------------------------------------
JSONDecodeError                           Traceback (most recent call last)
<ipython-input-183-a61a3a11c21f> in <module>
----> 1 json.loads(v)
/opt/anaconda3/envs/work_area/lib/python3.7/json/__init__.py in loads(s, encoding, cls, object_hook, parse_float, parse_int, parse_constant, object_pairs_hook, **kw)
    346             parse_int is None and parse_float is None and
    347             parse_constant is None and object_pairs_hook is None and not kw):
--> 348         return _default_decoder.decode(s)
    349     if cls is None:
    350         cls = JSONDecoder
/opt/anaconda3/envs/work_area/lib/python3.7/json/decoder.py in decode(self, s, _w)
    335 
    336         """
--> 337         obj, end = self.raw_decode(s, idx=_w(s, 0).end())
    338         end = _w(s, end).end()
    339         if end != len(s):
/opt/anaconda3/envs/work_area/lib/python3.7/json/decoder.py in raw_decode(self, s, idx)
    351         """
    352         try:
--> 353             obj, end = self.scan_once(s, idx)
    354         except StopIteration as err:
    355             raise JSONDecodeError("Expecting value", s, err.value) from None
JSONDecodeError: Expecting property name enclosed in double quotes: line 1 column 2 (char 1)

我该如何解决此问题？

Answer 1

这是因为在字符串中使用了撇号而不是引号的

小建议谷歌你的错误。我输入了

需要用双引号括起来的属性名称区块报价

进入谷歌，发现了另一个回答您问题的问题Python/Json：要求属性名用双引号括起来