Firebase函数在访问firestore时崩溃

Question

您能在下面的代码中找到一个错误吗？

const functions = require("firebase-functions");
const admin = require("firebase-admin");
admin.initializeApp();

exports.GetShort = functions.https.onRequest((request, response) => {
response.header("Access-Control-Allow-Origin", "*");
longURL = request.query.long
functions.logger.info("url is - " ,longURL)
SaveToDB(longURL)
})

function SaveToDB(link){
functions.logger.info("here")
admin.firestore().collection("url").where("urlNames","array_contains",link).get().then(

function(querySnapshot){
functions.logger.info("snap, " ,querySnapshot)
querySnapshot.forEach(function(doc) {
functions.logger.info("things :  " ,doc.id, " => ", doc.data())
// doc.data() is never undefined for query doc snapshots
console.log(doc.id, " => ", doc.data());
});
}
) .catch(function(error) {
functions.logger.info("Error getting documents: ", error);
});
}

在点击以上功能后，firebase功能日志显示日志，直到>；这里">。在那之后，它崩溃了，没有任何日志/stacktrace。

下面是函数目录中packages.json的内容。

{
"name": "functions",
"description": "Cloud Functions for Firebase",
"scripts": {
"lint": "eslint .",
"serve": "firebase emulators:start --only functions",
"shell": "firebase functions:shell",
"start": "npm run shell",
"deploy": "firebase deploy --only functions",
"logs": "firebase functions:log"
},
"engines": {
"node": "14"
},
"main": "index.js",
"dependencies": {
"firebase-admin": "^9.8.0",
"firebase-functions": "^3.14.1"
},
"devDependencies": {
"eslint": "^7.6.0",
"eslint-config-google": "^0.14.0",
"firebase-functions-test": "^0.2.0"
},
"private": true
}

Answer 1

我建议您观看关于"JavaScript承诺"；从Firebase系列视频中了解如何管理云函数的生命周期以及如何处理对异步方法的调用。

特别是，对于HTTPS云函数，您需要以send()、redirect()或end()结束它。

因此，您的代码可以进行如下调整：

exports.GetShort = functions.https.onRequest((request, response) => {
response.header("Access-Control-Allow-Origin", "*");
const longURL = request.query.long;
functions.logger.info("url is - ", longURL)
SaveToDB(longURL)
.then(() => {
response.status(200).send('Saved to DB');
})
.catch(error => {
// See video series
response.status(500).send(error);
})
})

function SaveToDB(link) {
functions.logger.info("here")
return admin.firestore().collection("url").where("urlNames", "array_contains", link).get()
.then(querySnapshot => {
functions.logger.info("snap, ", querySnapshot)
querySnapshot.forEach(function (doc) {
functions.logger.info("things :  ", doc.id, " => ", doc.data())
// doc.data() is never undefined for query doc snapshots
console.log(doc.id, " => ", doc.data());

// => Here, depending on your real functional requirements, you may need to use Promise.all()

});
return null;
}
).catch(function (error) {
functions.logger.info("Error getting documents: ", error);
// Throw an error
});
}

Answer 2

好吧，我发现了问题。有时愚蠢的事情会制造周围的大部分噪音。代替"；数组包含"；，我写了"；array_包含"；。