我想分离这个列表
[1000011]
并将其转换为
["1", "0000", "11"]
itertools
有一个groupby()
方法,它应该完全按照您的意愿执行。
from itertools import groupby
vals = [1000011]
splitVals = []
for val in vals:
splitVals.extend(''.join(g) for k,g in groupby(str(val)))
print(splitVals)
或者,如果您愿意,您可以将for
循环压缩为一行:
splitVals = [''.join(g) for val in vals for k,g in groupby(str(val))]
演示:在线试用!
您可以使用itertools.groupby
:
l = [1000011]
from itertools import groupby
[[''.join(g) for k,g in groupby(str(x))] for x in l]
输出:['1', '0000', '11']
如果输入列表中有几个值:
输入:l = [1000011, 1221]
输出:[['1', '0000', '11'], ['1', '22', '1']]