我必须拆分数据列,并与员工和经理建立关系。
表经理详细信息:
数据 | 员工 | 经理 |
---|---|---|
imp/imp2/imp3/imp4 | imp2 | notimp4 |
notimp1/notimp2/notimp3/notimp4 | imp3 | >td style="text-align:center;">imp4
如果我正确理解问题,您只需要一个LAG()
和递归CTE:中分隔符的位置
表:
CREATE TABLE ManagerDetails (id int, data varchar(1000))
INSERT INTO ManagerDetails (id, data)
VALUES
(1, 'imp/imp2/imp3/imp4'),
(2, 'notimp1/notimp2/notimp3/notimp4')
声明:
DECLARE @separator varchar(1) = '/';
WITH rCTE AS(
SELECT
d.id,
1 as [level] ,
d.data,
CAST(1 AS int) AS index1,
CHARINDEX(@separator, CONCAT(d.data, @separator)) AS index2
FROM ManagerDetails d
UNION ALL
SELECT
r.id,
r.[level] + 1,
r.data,
CAST(r.index2 + LEN(@separator) AS int),
CHARINDEX(@separator, CONCAT(r.data, @separator), r.index2 + 1)
FROM rCTE r
WHERE CHARINDEX(@separator, CONCAT(r.data, @separator), r.index2 + 1) > 0
)
SELECT
id AS Id,
SUBSTRING(CONCAT(data, @separator), 1, index2 - 1) AS [Value],
LAG(SUBSTRING(CONCAT(data, @separator), index1, index2 - index1)) OVER (PARTITION BY id ORDER BY level DESC) AS [Manager],
SUBSTRING(CONCAT(data, @separator), index1, index2 - index1) AS [Employee]
FROM rCTE
ORDER BY id, level DESC
OPTION (MAXRECURSION 0)
结果:
Id Value Manager Employee
---------------------------------------------------
1 imp/imp2/imp3/imp4 imp4
1 imp/imp2/imp3 imp4 imp3
1 imp/imp2 imp3 imp2
1 imp imp2 imp
2 notimp1/notimp2/notimp3/notimp4 notimp4
2 notimp1/notimp2/notimp3 notimp4 notimp3
2 notimp1/notimp2 notimp3 notimp2
2 notimp1 notimp2 notimp1