我正在使用HTTPCLIENT来自动化我的项目Web服务，并在获得csrf令牌后尝试登录，但我从响应中得到了这个错误，即使经过这么多次尝试，我也无法修复这个错误。
restClient = new RestClient();
HashMap<String, String> headerMaps = new HashMap<String, String>(); // Add header values
headerMaps.put("Content-Type", "application/json");
headerMaps.put("Connection", "keep-alive");
headerMaps.put("csrfToken", "test12");
// Jackson API : to convert java class object into JSON
ObjectMapper mapper = new ObjectMapper();
Users users = new Users("test@test.com", "abcd");
// Object to Jsonfile :mapper.writeValue(new
File("C:/NewEclipse/Projectn/src/main/java/com/qa/data/users.json"),users);
// Object to json in String:String usersJsonString = mapper.writerWithDefaultPrettyPrinter()
.writeValueAsString(users);
System.out.println("Users json value is----> " + usersJsonString);
// Call the Post method
closeableHttpResponse = restClient.postLogin(url, usersJsonString,headerMaps);
String responseString = EntityUtils.toString(closeableHttpResponse.getEntity(), "UTF-8");
System.out.println("Value of RESPONSE STRING----> " + responseString);
JSONObject responseJson = new JSONObject(responseString); //Here I am getting error mentioned in subject
我得到的JSON值也是正确的：
{"电子邮件"："test@test.com&"；，"密码"："abcd"；}
hooray我自己找到了这个问题的解决方案，现在它运行良好
我们需要在标题中传递一个cookie，如下所示：
headerMaps.put("cookie","_csrf=value; connect.sid=value; csrfToken=value")