rich.table返回错误的结果数

Question

我正在逐年收集电影信息。当我尝试打印语句时，它会打印所有100部电影，但当我使用rich.table打印时，我只得到第一部电影。

import requests
from bs4 import BeautifulSoup
from rich.table import Table
from rich.console import Console
table = Table()
url = 'https://www.rottentomatoes.com/top/bestofrt/?year='
year = input('Top 100 Movies for Which Year? ')
response = requests.get(url + year)
html = response.text
soup = BeautifulSoup(html, 'lxml')
containers = soup.find_all('table', class_='table')
for container in containers:
for row in container.find_all('tr')[1:]:
movie_rank = row.find('td', class_='bold')
movie_rank = movie_rank.text
movie_name = row.find('a', class_='unstyled articleLink')
movie_name = movie_name.text.strip()
movie_name = movie_name.strip('(' + year + ')')
movie_rating = row.find('span', class_='tMeterScore')
movie_rating = movie_rating.text
# print(f'{movie_rank} {movie_name.strip()} - rating:{movie_rating}')
table.add_column('Rank')
table.add_column('Movie')
table.add_column('Rating')
# problem is here     
table.add_row(movie_rank, movie_name, movie_rating)

console = Console()
console.print(table)
break

Answer 1

循环一次迭代后立即终止循环，构建后应打印一次表。此外，还应添加一次列(而不是每次迭代(。比如

import requests
from bs4 import BeautifulSoup
from rich.table import Table
from rich.console import Console
table = Table()
table.add_column('Rank')
table.add_column('Movie')
table.add_column('Rating')
url = 'https://www.rottentomatoes.com/top/bestofrt/?year='
year = input('Top 100 Movies for Which Year? ')
response = requests.get(url + year)
html = response.text
soup = BeautifulSoup(html, 'lxml')
containers = soup.find_all('table', class_='table')
for container in containers:
for row in container.find_all('tr')[1:]:
movie_rank = row.find('td', class_='bold')
movie_rank = movie_rank.text
movie_name = row.find('a', class_='unstyled articleLink')
movie_name = movie_name.text.strip()
movie_name = movie_name.strip('(' + year + ')')
movie_rating = row.find('span', class_='tMeterScore')
movie_rating = movie_rating.text
table.add_row(movie_rank, movie_name, movie_rating)
console = Console()
console.print(table)