如果包含在ES6中的字符串中，则返回True

Question

如果在ES6中找到这些字符串中的location.pathname，我如何返回true？

const noActionMenuRoutes = [
'/master/employees',
'/employees/dashboard',
'/employees/requests',
'/projects/myprojects',
];
const noActionMenus = () => {
if (location.pathname.some(noActionMenuRoutes)) {
return true;
} else {
return false;
}
};

Answer 1

使用findIndex

return noActionMenuRoutes.findIndex(el => el.includes(location.pathname)) != -1;

Answer 2

您可以使用Javascript数组includes或indexOf函数。

if (noActionMenuRoutes.some(route => location.pathname.includes(route)))

if (noActionMenuRoutes.some(route => location.pathname.indexOf(route) !== -1)

Answer 3

您可以使用string.includes()来确定是否可以在另一个字符串中找到一个字符串。

由于noActionMenuRoutes是一个数组，因此对其进行迭代并根据每个字符串进行验证

const noActionMenus = () => {
return noActionMenuRoutes.some(x => location.pathname.includes(x))
};

Answer 4

const noActionMenuRoutes = [
'/master/employees',
'/employees/dashboard',
'/employees/requests',
'/projects/myprojects',
];
const noActionMenus = () => noActionMenuRoutes.some(path => location.pathname.includes(path));
console.log(noActionMenus() )