尝试调用数据库管理系统中的函数时，出现未定义的引用错误以及退出状态错误

Question

所以我试图调用一个函数，该函数在newStudent函数中创建一个评估类对象。理想情况下，目标是运行newStudent函数，在达到级别选择后，它将调用相应的makeAssess函数。然后，每个makeAssess函数都会递归地调用自己，直到每个级别的总权重为100，然后转到下一个makeAssess功能。所有makeAssess功能在项目开始时就已经定义好了。

编辑：我正在使用带有GNUGCC编译器的CodeBlocks。这两个错误是"|未定义对"makeassessCH(("的引用|"；以及"|错误：ld返回1退出状态|"；

MPE:

//Relevant libraries
#include <iostream>
#include <fstream>
using namespace std;
int option;
void newStudent();
void makeassessH();
void makeassessI();
void makeassessC();
class Student {
public:
int stuNum;
std::string stuName;
int startDate;
int endDate;
string progofStudy;
char level;
};
class Assessment{
public:
std::string title;
int weight;
double grade;
string deadline;
};
int main()
{
//The option page
while (option != 5) {
cout << "nPlease choose an optionn"
"1. Add new studentsn"
"2. Student Loginn"
"3. Staff Loginn"
"4. Admin Viewn"
"5. Exitn"
"Enter option: ";
cin >> option;
if (option == 1) {
newStudent();
} else if (option == 5)
return 0;
}
}

void newStudent() {
Student stu;
string studentName = stu.stuName;
cout << "Please enter in your student number: ";
cin >> stu.stuNum;
cout << "Please enter in your name: ";
cin.ignore();
getline (cin, studentName);
cout << "Please enter in your start date: ";
cin >> stu.startDate;
cout << "Please enter in your end date: ";
cin >> stu.endDate;
cout << "Please enter in your programme of study: ";
cin.ignore();
getline(cin, stu.progofStudy);
cout << "Please enter your level of study: ";
cin >> stu.level;
if(stu.level == toupper('h')){
makeassessH();
makeassessI();
makeassessC();
}else if (stu.level == toupper('i')){
makeassessI();
makeassessC();
}else if(stu.level == toupper('c')) {
makeassessC();
}
}
void makeassesH(){
Assessment assessmentH;
cout << "Assessment title: ";
cin.ignore();
getline (cin, assessmentH.title);
cout << "Assessment weighting: ";
cin >> assessmentH.weight;
cout << "Assessment grade: ";
cin >> assessmentH.grade;
cout << "Assessment deadline: ";
cin >> assessmentH.deadline;
}
void makeassessI(){
Assessment assessmentI;
cout << "Assessment title: ";
cin.ignore();
getline (cin, assessmentI.title);
cout << "Assessment weighting: ";
cin >> assessmentI.weight;
cout << "Assessment grade: ";
cin >> assessmentI.grade;
cout << "Assessment deadline: ";
cin >> assessmentI.deadline;
}
void makeassessC(){
Assessment assessmentC;
cout << "Assessment title: ";
cin.ignore();
getline (cin, assessmentC.title);
cout << "Assessment weighting: ";
cin >> assessmentC.weight;
cout << "Assessment grade: ";
cin >> assessmentC.grade;
cout << "Assessment deadline: ";
cin >> assessmentC.deadline;
int totalWeight = totalWeight + assessmentC.grade;
}

Answer 1

错误消息告诉您(以及我们所有人(，您已声明一个名为的函数

void makeassessH()

但您从未定义。您确实有一个名为的函数

void makeassesH()

但拼写不一样。