在单独的线程Signals from和to循环中运行异步循环

Question

我正在尝试制作一个在后台与几个BLE设备通信的UI。为此，我实现了一个单独的线程，它运行asyncio.loop。这是必要的，因为我使用惨淡的0.9.1来连接设备。

使用信号和插槽将数据从UI线程获取到工作线程效果良好。然而，它并没有朝着另一个方向发展。据我所知，这是因为线程正忙于运行循环，并且从未停止过这样做。因此，它无法处理来自UI线程的输入。

下面是一个显示问题的示例代码。

在运行asyncio循环时，有什么方法可以处理线程中的输入槽吗？

import sys
from PyQt5.QtWidgets import QWidget, QPushButton, QApplication, QVBoxLayout
from PyQt5.QtCore import QThread, QObject, pyqtSignal, pyqtSlot
import asyncio
class Test_Thread(QObject):
signal_back = pyqtSignal(int)
def __init__(self,
loop: asyncio.AbstractEventLoop,
parent=None):
super(Test_Thread, self).__init__(parent)
self.text = "Task1 not configured"
self.loop = loop
self.counter = 0
@pyqtSlot(str)
def set_text_slot(self, txt):
self.text = txt
async def do_stuff1(self):
while True:
print(self.text)
await asyncio.sleep(2.0)
async def do_stuff2(self):
while True:
self.counter += 1
self.signal_back.emit(self.counter)
await asyncio.sleep(1.0)
def work(self):
#run the event loop
try:
asyncio.ensure_future(self.do_stuff1(), loop=self.loop)
asyncio.ensure_future(self.do_stuff2(), loop=self.loop)
self.loop.run_forever()
finally:
print("Disconnect...")

class Window(QWidget):
set_text_signal = pyqtSignal(str)
def __init__(self, parent=None):
super(Window, self).__init__()
self.initUi()
self.startThread()
def initUi(self):
layout = QVBoxLayout()
self.button = QPushButton('User input')
self.button.clicked.connect(self.sendtotask)
layout.addWidget(self.button)
self.setLayout(layout)
self.show()
def startThread(self):
loop = asyncio.get_event_loop()
self.asyciothread = Test_Thread(loop)
self.thread = QThread()
self.asyciothread.moveToThread(self.thread)
self.set_text_signal.connect(self.asyciothread.set_text_slot)
self.asyciothread.signal_back.connect(self.receivefromthread)
self.thread.started.connect(self.asyciothread.work)
self.thread.start()
@pyqtSlot(int)
def receivefromthread(self, number):
print(str(number))
def sendtotask(self):
self.set_text_signal.emit("Task: Configured")

if __name__ == "__main__":
app = QApplication(sys.argv)
ui = Window()
ui.show()
sys.exit(app.exec_())

Answer 1

没有必要使用线程与Qt一起使用异步，因为有像asyncqt和qasync这样的库可以启用它：

import asyncio
import sys
from PyQt5.QtWidgets import QWidget, QPushButton, QApplication, QVBoxLayout
from PyQt5.QtCore import QObject, pyqtSignal, pyqtSlot
from asyncqt import QEventLoop
# from qasync import QEventLoop

class Worker(QObject):
signal_back = pyqtSignal(int)
def __init__(self, loop: asyncio.AbstractEventLoop, parent=None):
super(Worker, self).__init__(parent)
self.text = "Task1 not configured"
self.loop = loop
self.counter = 0
@pyqtSlot(str)
def set_text_slot(self, txt):
self.text = txt
async def do_stuff1(self):
while True:
print(self.text)
await asyncio.sleep(2.0)
async def do_stuff2(self):
while True:
self.counter += 1
self.signal_back.emit(self.counter)
await asyncio.sleep(1.0)
def work(self):
asyncio.ensure_future(self.do_stuff1(), loop=self.loop)
asyncio.ensure_future(self.do_stuff2(), loop=self.loop)

class Window(QWidget):
set_text_signal = pyqtSignal(str)
def __init__(self, parent=None):
super(Window, self).__init__()
self.initUi()
self.start_task()
def initUi(self):
layout = QVBoxLayout(self)
self.button = QPushButton("User input")
self.button.clicked.connect(self.sendtotask)
layout.addWidget(self.button)
def start_task(self):
loop = asyncio.get_event_loop()
self.worker = Worker(loop)
self.set_text_signal.connect(self.worker.set_text_slot)
self.worker.signal_back.connect(self.receive_from_worker)
self.worker.work()
@pyqtSlot(int)
def receive_from_worker(self, number):
print(str(number))
def sendtotask(self):
self.set_text_signal.emit("Task: Configured")

if __name__ == "__main__":
app = QApplication(sys.argv)
loop = QEventLoop(app)
asyncio.set_event_loop(loop)
ui = Window()
ui.show()
with loop:
loop.run_forever()