从REST API返回数组中的前2个json名称/值对

Question

场景：我有两个REST端点，

https://myrestapi/user/names和https://myrestapi/user/age

/names端点包含一个JSON数组，如下所示：

{
"0x0": "John",
"0x1": "Cassy",
"0x2": "Christopher",
"0x3": "Jarred",
"0x4": "Simon",
"0x5": "Eddy",
"0x6": "Lara",
"0x7": "Marcel",
"0x8": "Simone"
}

/age端点包含一个JSON数组，如下所示：

{
"0x0": "36",
"0x1": "24",
"0x2": "21",
"0x3": "29",
"0x4": "24",
"0x5": "38",
"0x6": "45",
"0x7": "37",
"0x8": "26"
}

运行以下代码，我可以显示阵列中的所有数据：

$.when( 
$.getJSON( "https://myrestapi/user/names" ), 
$.getJSON( "https://myrestapi/user/age" )
).done(( a1, a2 ) => {
// a1[0] gets list of name
// a2[0] gets list of ages
console.log(a1[0])
console.log(a2[0])
})

如果我只想要前两对的名字和年龄呢？

示例：[{"user_id"："0x0"，"name"："John"，"age"：36}，{"用户id"："0x1"，"姓名"："凯西"，"年龄"：24}]

有人能提供一些方向吗？

Answer 1

试试这个，你可以定义你想在for循环中列出的用户数量，例如i<3将产生3个名称/值对

let names = {
"0x0": "John",
"0x1": "Cassy",
"0x2": "Christopher",
"0x3": "Jarred",
"0x4": "Simon",
"0x5": "Eddy",
"0x6": "Lara",
"0x7": "Marcel",
"0x8": "Simone"
}

let ages = {
"0x0": "36",
"0x1": "24",
"0x2": "21",
"0x3": "29",
"0x4": "24",
"0x5": "38",
"0x6": "45",
"0x7": "37",
"0x8": "26"
}
let result = [];
for(let i = 0; i < 3; i++){
result.push({'user_id': Object.keys(names)[i], 'name': Object.values(names)[i], 'age': Object.values(ages)[i]})
}
console.log(result)

Answer 2

API返回JSON对象，而不是JSON数组。因此，不存在"；第一个N〃；元素。如果您更改API代码以返回JSON数组，那么您可以获得；前2个元素"；现在，你可以想到你想选择的ID列表：

const listOfIds = ['0x0', '0x1'];
const dataYouWant = listOfIds.map(id => ({
user_id: id,
name: a1[id],
age: a2[id],
}));