Pytest使用fixture返回值，而不是函数位置

Question

我想为HighSchool类中的tenth_standard方法执行pytest：

Class HighSchool():
...
def tenth_standard(self):
return f"I-am-studying-in-{self.school}-at-{self.country}"

我想使用@pytest.fixture和@pytest.mark.parametrize来执行pytest，我的代码如下：

@pytest.fixture(scope="function")
def expected(request):
return f"I-am-studying-in-{school}-at-{country}"
@pytest.fixture(scope="function")
def school(request):
return request.param
@pytest.fixture(scope="function")
def country(request):
return request.param


@pytest.mark.parametrize("school", ["abcd", "efgh"], indirect=True)
@pytest.mark.parametrize("country", ["India", "Japan"], indirect=True)
def test_tenthstandard(school, country, expected):
b = HighSchool(school=school, country=country)
assert expected == b.tenth_standard()

当我运行这个程序时，我会得到一个AssertionError，如下所示：

AssertionError: assert ('I-am-studying-in-<function school at 0x7f6b858a63a0>-at-<function country at '0x7f6b858a6280>) == 'I-am-studying-in-abcd-at-India'

我想修复expected fixture以返回值，而不是function at XXX location。有人能帮我怎么修吗？

Answer 1

您的expectedfixture并没有从其他fixture中获取参数，而是只获取fixture函数，这当然不是您想要的。你可以"；导出"；expected夹具与其他夹具不同，因此它将使用相同的参数自动参数化：

@pytest.fixture
def school(request):
return request.param
@pytest.fixture
def country(request):
return request.param
@pytest.fixture
def expected(school, country):
return f"I-am-studying-in-{school}-at-{country}"
@pytest.mark.parametrize("school", ["abcd", "efgh"])
@pytest.mark.parametrize("country", ["India", "Japan"])
def test_tenthstandard(school, country, expected):
b = HighSchool(school=school, country=country)
assert expected == b.tenth_standard()

请注意，在这种情况下，您甚至可以跳过indirect=True部分，因为expected夹具已经获得了正确的值。

附带说明：在测试中复制应用程序逻辑通常不是一个好主意，就像这里所做的那样。通过这种方式，错误可以很容易地传播到测试中，而不会被发现
(尽管在这种情况下，这可能只是由于一个愚蠢的例子(