转换为参数"name"的"int"失败

Question

对此有解决方案吗？

async def cosmetic(ctx, name : int):
response = requests.get("https://fortnite-api.com/v2/cosmetics/br")
embed=discord.Embed(
title=f"{name}", color=0x9c3030
)
embed.add_field(f'Rarity: {BrCosmeticRarity}')
await ctx.send(embed=embed)

Answer 1

您通过显式地将name转换为int

async def cosmetic(ctx, name : int):

---

name不应该是int类型，因为它可能是一个字符串。要解决您的问题，请在函数声明中为name设置正确的类型

---

async def cosmetic(ctx, name : str):

---

async def cosmetic(ctx, name : str):
response = requests.get("https://fortnite-api.com/v2/cosmetics/br")
embed=discord.Embed(
title=f"{name}", color=0x9c3030
)
embed.add_field(f'Rarity: {BrCosmeticRarity}')
await ctx.send(embed=embed)