我目前创建了一个函数，它接受两个参数。
function p = matr(x, phi)
x_dir = linspace(0, x, 1);
r = linspace(0, phi, 1);
p = zeros(800, 2);
p(1:400, 1) = p(1:400, 1) + x_dir.';
p(401:800, 2) = p(401:800, 2) + r.';
end
返回给定输入的矩阵:
path = trajectory(10, pi/2)
path =
0 0
0.0251 0
0.0501 0
0.0752 0
0.1003 0
0.1253 0
0.1504 0
0.1754 0
0.2005 0
0.2256 0
0.2506 0
0.2757 0
0.3008 0
0.3258 0
0.3509 0
0.3759 0
0.4010 0
0.4261 0
0.4511 0
0.4762 0
0.5013 0
0.5263 0
0.5514 0
0.5764 0
0.6015 0
0.6266 0
0.6516 0
0.6767 0
0.7018 0
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0.7519 0
0.7769 0
0.8020 0
0.8271 0
0.8521 0
0.8772 0
0.9023 0
0.9273 0
0.9524 0
0.9774 0
1.0025 0
1.0276 0
1.0526 0
1.0777 0
1.1028 0
1.1278 0
1.1529 0
1.1779 0
1.2030 0
1.2281 0
1.2531 0
1.2782 0
1.3033 0
1.3283 0
1.3534 0
1.3784 0
1.4035 0
1.4286 0
1.4536 0
1.4787 0
1.5038 0
1.5288 0
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1.5789 0
1.6040 0
1.6291 0
1.6541 0
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但是我想修改这个函数，使它可以两个列表，如:
trajectory([x1, x2, x3, ... xn], [phi1, phi2, phi3, ..., phin])
并创建如下的矩阵:
trajectory =
x1 0
x1+k 0
. 0
. 0
x1_n 0
0 phi1
0 phi1+k
0 .
0 .
0 phi1_n
x2 0
x2+k 0
. 0
. 0
x2_n 0
0 phi2
0 phi2+k
0 .
0 .
0 phi2_n
等等。所以我在想是否有一种更自动的方式来扩展矩阵，这样就可以提供两个列表作为输入参数，矩阵根据列表的元素展开。
function p = matr(x, phi)
p = zeros(800*length(x), 2);
for ii = 1:length(x)
x_dir = linspace(0, x(ii), 400);
r = linspace(0, phi(ii), 400);
p((800*(ii-1)+1):(800*(ii-1)+400), 1) = x_dir;
p((800*ii-399):(800*ii), 2) = r;
end
end
或
function p2 = matr_compound(x, phi)
p2 = [];
for ii = 1:length(x)
p2 = [p2; matr(x(ii), phi(ii))];
end
end