如何遍历列表中的字典，并将键值提取到单独的列表中

Question

我试图在列表中匹配来自不同字典的键值，并将它们作为单独的列表。下面是示例格式

originallist=[
{"A":"Autonomous","C":"Combined","D":"Done"},
{"B":"Bars","A":"Aircraft"},
{"C":"Calculative"}
]
#Note: The dictionaries present in the original list may vary in number
#I was trying to acheive the below format
A=["Autonomous","Aircraft"]
B=["Bars"]
C=["Calculative","Combined"]
D=["Done"]

提前感谢您的帮助

Answer 1

最好的选择是使用defaultdict。

from collections import defaultdict
out = defaultdict(list)
#data is the list in question
for rec in data:
for key,value in rec.items():
out[key].append(value)

defaultdict在键不存在的情况下返回默认值。dict.items是返回键值对和迭代器的方法。

你可以用pandas来做得更快，但是除非你有一个庞大的数据集，否则这将是过度杀伤。