如何返回对象，如果没有发现值，否则做一些循环条件和返回对象使用react和typescript? &g

Question

嗨，我有一个像下面这样的对象数组，

const arr_obj = [
{
id: '1',
jobs: [
{
completed: false,
id: '11',
run: {
id: '6',
type: 'type1',
},
},
{
completed: true,
id: '14',
run: {
id: '17',
type: 'type1',
},
},
{
completed: false,
id: '12',
run: {
id: '7',
type: 'type2',
},
},
],
},
{
id: '2',
jobs: [
{
completed: true,
id: '13',
run: {
id: '8',
type: 'type2',
},
},
{
completed: true,
id: '16',
run: {
id: '9',
type: 'type1',
},
}, 
{
completed: true,
id: '61',
run: {
id: '19',
type: 'type1',
},
},
],
},
{
id: '3',
jobs: [
{
completed: false,
id:'111',
run: {
id: '62',
type: 'type1',
},
}, 
],
},
],

现在我必须从arr_obj中获取id它匹配这个数组

const arr_ids =("1","2")

，其运行类型为"type1"所有作业都没有完成:false

所以预期输出是"2">

下面的代码可以工作，

const filtered_arr_obj = arr_obj.filter(obj => {
if (arr_ids.includes(obj.id)) {
const jobs = obj.jobs.filter(job => job.run.type === "type1");
if (jobs.length > 0) {
return jobs.every(job => job.completed === true);
}
return false;
}
return false;
});
let filtered_ids = filtered_arr_obj.map(obj => obj.id);
console.log("filteredIds", filteredIds)  //2

现在的问题是，如果没有运行和运行类型"type"对于job，我还想过滤没有作业运行类型为"type1">

的对象所以考虑下面的例子

const arr_obj = [｛id: ' 1 ',工作:(｛完成:假的,id:"11",运行:{id:"6",类型:类型1,}，}，｛完成:没错,id:"14",运行:{id:"17",类型:类型1,},

},
{
completed: false,
id: '12',
run: {
id: '7',
type: 'type2',
},
},
],
},
{
id: '2',
jobs: [
{
completed: true,
id: '13',
run: {
id: '8',
type: 'type2',
},
},
{
completed: true,
id: '16',
run: {
id: '9',
type: 'type1',
},
}, 
],
},
{
id: '3',
jobs: [
{
completed: false,
id: '111',
run: {
id: '62',
type: 'type1',
},
},
],
},
{
id: '4',
jobs: [
{
completed: true,
id: '121',
run: {
id: '66',
type: 'type2',
},
},
],
},

),和

arr_ids =("1"、"2"、"4")所以期望输出是

("2","4")这里4也被选中了因为arr_ids有"4"而ar_obj中的对象id为&;4&;没有运行类型为&;type1&;的作业。

我如何修改上面的代码片段来包含这个条件?有人能帮我一下吗?谢谢。

我是一个编程新手，请一定回答这个问题。

Answer 1

看起来，当id出现在arr_ids中，如果作业长度为<= 1，那么我们应该过滤它，否则我们过滤类型1的作业并检查是否全部完成。

const arr_obj = [
{
id: '1',
jobs: [
{
completed: false,
id: '11',
run: {
id: '6',
type: 'type1',
},
},
{
completed: true,
id: '14',
run: {
id: '17',
type: 'type1',
},
},
{
completed: false,
id: '12',
run: {
id: '7',
type: 'type2',
},
},
],
},
{
id: '2',
jobs: [
{
completed: true,
id: '13',
run: {
id: '8',
type: 'type2',
},
},
{
completed: true,
id: '16',
run: {
id: '9',
type: 'type1',
},
}, 
{
completed: true,
id: '61',
run: {
id: '19',
type: 'type1',
},
},
],
},
{
id: '3',
jobs: [
{
completed: false,
id:'111',
run: {
id: '62',
type: 'type1',
},
}, 
],
},
{
id: '4',
jobs: [
{
completed: true,
id: '121',
run: {
id: '66',
type: 'type2',
},
},
],
},
];
const arr_ids = ["1", "2", "4"];
const filtered_arr_obj = arr_obj.filter(obj => {
if (arr_ids.includes(obj.id)) {
if(obj.jobs.length <= 1 ){
return true;
}
else {
const type1jobs = obj.jobs.filter(job => job.run.type === "type1");
return type1jobs.every(job => job.completed );
}
}
return false;
});
let filtered_ids = filtered_arr_obj.map(obj => obj.id);
console.log("filteredIds", filtered_ids)