Javafx - AlwaysonTop之间的切换

Question

我想要一个选项来切换alwaysontoptrue/false。但是，当我关闭并显示窗口时，它不会接管它。

@FXML
public void toggleAlwaysonTop(ActionEvent event){
try{
Worker.toggleAlwaysOnTop(); //changes boolean if it is always on top and saves it log
Stage stage = (Stage) ((Node)event.getSource()).getScene().getWindow(); //gets stage of settings window
Stage changer = Application.getPrimaryStage(); //gets primary stage of the Application
stage.close();
changer.close();
changer.show();

}catch (Exception e) {
System.out.println("Error bei der App Klicken von ModeButton. n error is: "+e);
e.printStackTrace();
}
}

在Application类中我使用:

primaryStage.setAlwaysOnTop(Worker.isItalwaysOnTop);

对于第二个窗口，当我通过按钮再次打开它时，它是否工作。但是如果我用stage.close()和stage.show()我有同样的问题。我使用类似的方法在暗/亮模式之间切换。这里它工作得很好。

Answer 1

哦，这其实很简单，你只需要使用stage.setAlwaysOnTop();和changer.requestFocus();(直接接管)

@FXML
public void toggleAlwaysonTop(ActionEvent event){
try{
Worker.toggleAlwaysOnTop(); //changes boolean if it is always on top and saves it log
Stage stage = (Stage) ((Node)event.getSource()).getScene().getWindow(); //gets stage of settings window
Stage changer = Application.getPrimaryStage(); //gets primary stage of the Application
stage.close();
changer.setAlwaysOnTop(Worker.isItalwaysOnTop);
changer.requestFocus();//Preventing that it does not take it over directly when you worked in another application before (sry I can't explain the Problem properly^^)

}catch (Exception e) {
System.out.println("Error bei der App Klicken von ModeButton. n error is: "+e);
e.printStackTrace();
}
}