有没有任何可能的方法来连接具有相同delimeter的拆分字符串

Question

是否有任何可能的方法来连接具有相同delimeter的拆分字符串？

例如，我有一个字符串，里面有句子

const str = "Edit the Expression & Text to see matches. Roll over matches or the expression for details? PCRE & JavaScript flavors of RegEx are supported! "

我想用句子分开。我就是这样。

str.split(/[.?!;]+s?/g)

我能用同样的delimeter把绳子连接起来吗？

str.split(/[.?!;]+s?/g).map(...).join(???)

谢谢！

Answer 1

您可以调用match来获得所使用的分隔符数组，然后使用reduce将数组连接回来并插入分隔符。

const str = `const str = "Edit the Expression & Text to see matches. Roll over matches or the expression for details? PCRE & JavaScript flavors of RegEx are supported! "`
const match = str.match(/[.?!;]+s?/g)
const result = str.split(/[.?!;]+s?/g).map(e => e).reduce((acc, curr, i) => (acc += curr + (match[i] || ""), acc), "")
console.log(result)

Answer 2

您可以将分隔符作为组进行拆分，并在根据需要更改第二部分后连接字符串。

const
str = "Edit the Expression & Text to see matches. Roll over matches or the expression for details? PCRE & JavaScript flavors of RegEx are supported! ",
result = str
.split(/([.?!;]+s*)/) 
.map((s, i) => s && i % 2 === 0 ? `<stong>${s}<strong>` : s)
.join('');
console.log(result);

Answer 3

执行多个拆分/联接

let str = "Edit the Expression & Text to see matches. Roll over matches or the expression for details? PCRE & JavaScript flavors of RegEx are supported!"
const delim=['.','?','!',';']
delim.forEach(d=>{
console.log(str.split(new RegExp(`[${d}]+\s?`))) // showing what split does
str = str.split(new RegExp(`[${d}]+\s?`)).map(s=>s).join(d)
})