Python字典附加值,如果键值对相同



我是python字典的新手,对键附加值有疑问。示例python字典如下所示。我怎么能追加值,如果键值对,ID &时间都一样吗?请参阅下面的预期结果。尝试了append(), pop(), update(),但没有得到预期的结果。谢谢你的帮助。


{
"Total": [
{
"ID": "ID_1000",
"time": 1000,
"name": {
"first_name": "John",
"last_name": "Brown"
}
},
{
"ID": "ID_5000",
"time": 5000,
"name": {
"first_name": "Jason",
"last_name": "Willams"
}
},
{
"ID": "ID_5000",
"time": 5000,
"name": {
"first_name": "Mary",
"last_name": "Jones"
}
},
{
"ID": "ID_1000",
"time": 1000,
"name": {
"first_name": "Michael",
"last_name": "Kol"
}
}
]
}

下面是预期的结果。


{
"Total": [
{
"ID": "ID_1000",
"time": 1000,
"name": [
{
"first_name": "John",
"last_name": "Brown"
},
{
"first_name": "Michael",
"last_name": "Kol"
}
]
},
{
"ID": "ID_5000",
"time": 5000,
"name": [
{
"first_name": "Jason",
"last_name": "Willams"
},
{
"first_name": "Mary",
"last_name": "Jones"
}
]
}
]
}

一种选择是使用一个中间字典,将id作为键。请注意,此代码不管理时间数据,因为不清楚是否要添加或期望什么。

import json
values = {
"Total": [
{
"ID": "ID_1000",
"time": 1000,
"name": {
"first_name": "John",
"last_name": "Brown"
}
},
{
"ID": "ID_5000",
"time": 5000,
"name": {
"first_name": "Jason",
"last_name": "Willams"
}
},
{
"ID": "ID_5000",
"time": 5000,
"name": {
"first_name": "Mary",
"last_name": "Jones"
}
},
{
"ID": "ID_1000",
"time": 1000,
"name": {
"first_name": "Michael",
"last_name": "Kol"
}
}
]
}
# first create a dictionary with the ids as keys
consolidated_names = {}
for total_value in values["Total"]:
id = total_value["ID"]
if id not in consolidated_names:
consolidated_names[id] = [total_value["name"]]
else:
consolidated_names[id].append(total_value["name"])
# then create the structure that you want
processed_values = []
for id in consolidated_names:
processed_values.append({"ID": id, "name": consolidated_names[id]})

print(json.dumps({"Total": processed_values}, indent=4))

结果:

{
"Total": [
{
"ID": "ID_1000",
"name": [
{
"first_name": "John",
"last_name": "Brown"
},
{
"first_name": "Michael",
"last_name": "Kol"
}
]
},
{
"ID": "ID_5000",
"name": [
{
"first_name": "Jason",
"last_name": "Willams"
},
{
"first_name": "Mary",
"last_name": "Jones"
}
]
}
]
}

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