使用Httpclient将数据发送到其参数不是复杂对象的WebApi

Question

这是我的webapi post请求

[HttpPost]
[Route("Create/{id}")]
public async Task<IActionResult> CreateContact(Guid id, string email, string fullName)
{
// code removed for brevity
}

我如何张贴contact对象到webapi?这是我的客户端。

using (var client = new HttpClient())
{
client.BaseAddress = new Uri("https://localhost:123");
client.DefaultRequestHeaders.Accept.Clear();
client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
var contact = new Contact() { Id = 12345, Email = "[e-mail]", FullName = "John" };
HttpResponseMessage response = await client.PostAsJsonAsync($"/api/Contact/Create/{contact.Id}", contact);
if (response.IsSuccessStatusCode)
{

}
else
{

}
}

Answer 1

不确定这是否是最好的，但它工作。在Route属性

处添加更多参数

[HttpPost]
[Route("Create/{id}/{email}/{fullName}")]
public async Task<IActionResult> CreateContact(Guid id, string email, string fullName)
{
// code removed for brevity
}

，然后在httpclient

HttpResponseMessage response = await client.PostAsJsonAsync($"/api/Contact/Create/{contact.Id}/{contact.Email}/{contact.FullName}", contact);

Answer 2

大家好，在WPI中使用[FromBody]。您可以将Contact作为对象发布

[HttpPost]
[Route("Create/{contact}")]
public async Task<IActionResult> CreateContact([FromBody]Contact contact)
{
// code removed for brevity
}

using (var client = new HttpClient())
{
client.BaseAddress = new Uri("https://localhost:123");
client.DefaultRequestHeaders.Accept.Clear();
client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
var contact = new Contact() { Id = 12345, Email = "[e-mail]", FullName = "John" };
var contactJson = JsonConvert.SerializeObject(contact);
var stringContent = new StringContent(contactJson , UnicodeEncoding.UTF8, "application/json");
HttpResponseMessage response = await client.PostAsync($"/api/Contact/Create/", stringContent);
if (response.IsSuccessStatusCode)
{

}
else
{

}
}