如果输入值相似，我如何从中返回多个结果

Question

例如：在这种情况下，需要最昂贵的物品。

d= (('Shirts',40000),('trousers',40000),('provisions',34000),('others',34000))
def pick_the_most_expensive_from_my_list(d):
material = '' 
price = None
for x,y in d:
if price is None:
price= y
material= x
while y > price:
price = y                           
material= x

return material,price

Answer 1

您可以先找到最大价格，然后返回具有该价格的对。

d= (('Shirts',40000),('trousers',40000),('provisions',34000),('others',34000))
def pick_the_most_expensive_from_my_list(d):
return [pair for pair in d if pair[1]==max([item[1] for item in d])]

输出

[('Shirts', 40000), ('trousers', 40000)]

Answer 2

您需要首先找到最大价格，然后过滤具有该价格的值。

d= (('Shirts',40000),('trousers',40000),('provisions',34000),('others',34000))
def pick_the_most_expensive_from_my_list(d):
if not d:
return None
max_v = max(d, key=lambda x:x[1])[-1]
return list(filter(lambda x: x[1]==max_v, d))

print(pick_the_most_expensive_from_my_list(d))

输出

[('Shirts', 40000), ('trousers', 40000)]

或使用字典

d= (('Shirts',40000),('trousers',40000),('provisions',34000),('others',34000))
def pick_the_most_expensive_from_my_list(d):
if not d:
return None
price = {}

for i in d:
if i[1] not in price:
price[i[1]] = [i]
else:
price[i[1]].append(i)

return price.get(max(price))

print(list(pick_the_most_expensive_from_my_list(d)))

Answer 3

def mostExpensiveItems():
items = [''] 
prices = [0] 
for currentItems, currentPrices in items:  
if currentPrices > prices[-1]: 
items.append(currentItems)
prices.append(currentPrices)
elif currentPrices == prices[-1]:
items.append(currentItems)
prices.append(currentPrices)
print(items)
print(prices)