使用Case语句比较四列，并在新列中添加最早的日期

Question

我试图有一个列，列出最早的日期的四列。我已经尝试了一个Case语句和一个应该列出s.Open_date的锡，相反，它将1/1/2020放在列中。这是数据

tin     S.Open_Date     LoanOpen    CCOpenDate    MortgageDate    EarliestDate
1        5/5/2015        11/19/2018    null        9/25/2017         1/1/2020

所以在上面的例子中，它应该有5/5/2015在最早的日期列。

我把整个查询放在下面。也就是说，除了Case语句外，查询中的所有内容都正常工作。有更好的方法吗?

select i.mem, min(s.open_date) as ShareOpenDate, min(l.loanopen) as LoanOpen, min(ecc.cc_opendate) as CCopenDate, min(m.MortgageDate) as MortgageDate,
Case
when (s.open_date > l.loanopen and s.open_date > ecc.cc_opendate AND s.open_date > m.MortgageDate) then s.open_date
when (l.loanopen > s.open_date and l.loanopen > ecc.cc_opendate AND l.loanopen > m.MortgageDate) then l.loanopen
when (ecc.cc_opendate > s.open_date and ecc.cc_opendate > l.loanopen AND ecc.cc_opendate > m.MortgageDate) then ecc.cc_opendate
when (m.MortgageDate > s.open_date and m.MortgageDate > l.loanopen AND m.MortgageDate > ecc.cc_opendate) then m.MortgageDate
else '1/1/2020' END as EarliestDate
from individual as i
inner join membershipparticipant as mp on i.individual_id=mp.individual_id and mp.participation_type=101
inner join share as s on mp.member_nbr=s.member_nbr
#Subquery to bring in loan information
left outer join (
select member_nbr, min(open_date) as loanopen
from loan as l
group by member_nbr
)l  on s.member_nbr=l.member_nbr
#Subquery to bring in CC Information
left outer join ( 
select savings_acct_nbr, min(open_date) as cc_opendate
from externalcreditcard
group by savings_acct_nbr
) ecc on s.member_nbr=ecc.savings_acct_nbr
Subquery to bring in mortgage information
left outer join (
select MC_PMT_MBR_NBR as MortgageMember, min(MC_Loan_Date) as MortgageDate
from EXTERNALMORTGAGEMC
group by MC_PMT_MBR_NBR
)m on s.member_nbr=m.MortgageMember
group by i.mem

Answer 1

最简单的方法是在SELECT中使用子查询，尽管这可能会对性能有一点影响:

SELECT
...
, (SELECT MIN(x)
FROM (VALUES
(l.loanopen),
(s.open_date),
(ecc.cc_opendate),
(m.MortgageDate),
('1/1/2020')
) AS v (x)) AS EarliestDate
FROM ...