如何调用内部方法

Question

在下面的代码中，我试图理解全局变量和局部变量之间的差异。运行时将生成以下错误:#

File "m:python lessonsglobalAndLocal_1.py", line 21, in globalVsLocal_1
self.g2()
NameError: name 'self' is not defined

注意

i want to call g2 from within g1

请告诉我如何调用方法g2()

:

class globalVsLocal_1:
def f1(self):
global a #this is to reference a variable declared in the global context.
print ("f1 a = %s"%(a)) # if global a was not declared in the first line, generates this line an error as variable a not defined is
a = a + 10            
print ("f1 a = %s"%(a))
def f2(self):
print("f2 a = %s"%(a))
def f3(self):
print("f3 b = %s"%(b))
#b = b + 1   #activating this line will yield an error. Because the absence of the keyword global. the print statement works immaculately without global keyword because it just reads the value without 
#manipulate it
print("f3 b = %s"%(b))
def g1(self):
def g2():
print("g2 b = %s "%(b))
g2()
a = 1
b = 20
obj = globalVsLocal_1()
obj.f1()
obj.f2()
obj.f3()
obj.g1()

Answer 1

g2()的作用域是函数g1()的局部作用域，因此您不能在外部调用它。在类定义的中间尝试调用g2()也是不寻常的。

class ...
def g1(self):
def g2():
print("g2 b = %s "%(b))
g2()

Answer 2

class globalVsLocal_1:
def f1(self):
global a #this is to reference a variable declared in the global context.
print ("f1 a = %s"%(a)) # if global a was not declared in the first line, generates this line an error as variable a not defined is
a = a + 10            
print ("f1 a = %s"%(a))
def f2(self):
print("f2 a = %s"%(a))
def f3(self):
print("f3 b = %s"%(b))
#b = b + 1   #activating this line will yield an error. Because the absence of the keyword global. the print statement works immaculately without global keyword because it just reads the value without 
#manipulate it
print("f3 b = %s"%(b))
def g1(self):
def g2():
print("g2 b = %s "%(b))
g2()
a = 1
b = 20
obj = globalVsLocal_1()
obj.f1()
obj.f2()
obj.f3()
obj.g1()

调用g2时缺少缩进。这会给出以下输出

f1 a = 1
f1 a = 11
f2 a = 11
f3 b = 20
f3 b = 20
g2 b = 20