在没有模型的情况下，如何在上传到S3之前更改django InMemoryUploadedFile的文件名

Question

环境

Django==3.24

DRF==3.11

boto3==1.16

django存储==1.10

---

我想在上传到s3之前更改文件名，而不保存在DB(模型)中。

我试过了。

# in Post request
files = request.FILES.getlist('files')
res = []
for file in files:
random_car = ''.join(random.SystemRandom().choice(string.ascii_letters + string.digits) for _ in range(8))
ext = file.name.split('.')[-1]
file_name = f'{random_car}.{ext}'
# -------- try start ---------
# I want to change file name to file_name
# This code throws an error.
# FileNotFoundError: [Errno 2] No such file or directory: '8.jpeg' -> 'kVuepnuR.jpeg'
os.rename(file.name, file_name)
# -------- try end ---------
file_path_within_bucket = os.path.join(
file_directory_within_bucket,
file.name
)
default_storage.save(file_path_within_bucket, file)
file_url = default_storage.url(file_path_within_bucket)
res.append(file_url)

如果InMemoryUploadedFile，我如何更改名称？

Answer 1

我找到了一种方法来解决它并分享它。

random_car = ''.join(random.SystemRandom().choice(string.ascii_letters + string.digits) for _ in range(8))
ext = file.name.split('.')[-1]
file_name = f'{random_car}.{ext}'
file_path_within_bucket = os.path.join(
file_directory_within_bucket,
f"{file_name}"
)

的istead

random_car = ''.join(random.SystemRandom().choice(string.ascii_letters + string.digits) for _ in range(8))
ext = file.name.split('.')[-1]
file_name = f'{random_car}.{ext}'

file_path_within_bucket = os.path.join(
file_directory_within_bucket,
file.name
)