将数字四舍五入到离最后一个数字最近的数组中的最高数字

Question

var counts = [2, 33, 61, 92, 125, 153, 184, 215, 245, 278, 306, 335, 365],
goal = 35;
let min = Math.min(...counts.filter(num => num >= goal));
console.log(min)

这是有效的，但在goal=400的情况下，我将返回365，因为它是数组中的最后一个数字

Answer 1

您可以找到所需的值，也可以在最后一个索引中获取值。

const
find = (array, value) => array.find((v, i, { length }) =>
v >= value || i + 1 === length
),
counts = [2, 33, 61, 92, 125, 153, 184, 215, 245, 278, 306, 335, 365];
console.log(find(counts, 35));
console.log(find(counts, 400));

如果undefined。

const
find = (array, value) => array.find(v => v >= value) ?? array.at(-1),
counts = [2, 33, 61, 92, 125, 153, 184, 215, 245, 278, 306, 335, 365];
console.log(find(counts, 35));
console.log(find(counts, 400));

Answer 2

这将为您提供高于目标的最小数字，如果没有高于目标的数字，则为计数中的最大数字

const counts = [2,33,61,92,125,153,184,215,245,278,306,335,365]
goal = 35;
const above_goal = counts.filter(num => num >= goal)

const min = above_goal.length === 0 ? Math.max(counts) : Math.min(above__goal)

console.log(min)