比较嵌套列表中包含的所有列表，只获取匹配的字符串

Question

我想比较嵌套列表中包含的所有列表，以便在末尾有对应的配对词who。

我用两个不同的列表来管理它，以获得每个列表中匹配的字符串。

这样：

listA = [['Test1','Test2','Test3'], ['Test1','Test4','Test2']]
listB = [['Test1','Test2','Test5'], ['Test10','Test4','Test2']]

我得到的结果是：

['Test1', 'Test2'] # Matched at [('Test1,'Test2'),'Test3'] -> [('Test1','Test2'),'Test5']
['Test2'] # Matched at ['Test1','Test4',('Test2')] -> ['Test1',('Test2'),'Test5']
['Test4', 'Test2'] # Matched at ['Test1',('Test4','Test2)] -> ['Test10',('Test4','Test2')]

在这个例子中，我们注意到"Test3、Test5和Test10"不在结果中，因为它们都与其他列表不匹配。

我想用一个嵌套列表来完成它。

list = [['Test1','Test2','Test3'], ['Test1','Test4','Test2'], ['Test1','Test2','Test5'], ['Test5','Test4','Test2']]

这里的代码我使用两个列表：

from collections import Counter
from itertools import takewhile, dropwhile

for x in listB:
for y in listA:
counterA = Counter(x)
counterB = Counter(y)

count = counterA + counterB
count = dict(count)
prompt_match = [k for k in count if count[k] == 2]
print(prompt_match)

这两个列表的代码并不完美，因为我有重复的列表。

Answer 1

您可以在列表理解中尝试set交集

from itertools import product
listA = [['Test1','Test2','Test3'], ['Test1','Test4','Test2']]
listB = [['Test1','Test2','Test5'], ['Test10','Test4','Test2']]
set(tuple(set(x)&set(y)) for x,y  in product(listA, listB))
# output
{('Test1', 'Test2'), ('Test2',), ('Test4', 'Test2')}
For nested list use below approach
from itertools import combinations
listA = [['Test1','Test2','Test3'], ['Test1','Test4','Test2'], ['Test1','Test2','Test5'], ['Test10','Test4','Test2']]
set(tuple(set(x)&set(y)) for x,y  in combinations(listA, 2))
# output
{('Test1', 'Test2'), ('Test2',), ('Test4', 'Test2')}