基于csv文件名的shutil移动

Question

嗨，伙计们，目前正在我的csv文件上基于文件名移动文件，但它总是先移动文件，然后读取文件名，所以它总是得到错误，就像这个一样已经存在

错误：目标路径"Sortir/Membuka kertas contekan/aug1_Data16_133_86.jpg"已存在

代码

import pandas as pd
data = pd.read_csv('train.csv')
filenames = data['filename'].values
filenames = filenames.tolist()
classes = data['class'].values
classes = classes.tolist()
print(filenames)
print(classes)
import shutil
import os
for index, row in data.iterrows():
print(row['filename'], os.path.join("Sortir",row['class']))
if not os.path.exists(os.path.join("Sortir",row['class'])):
print("[INFO] 'creating {}' directory".format(os.path.join("Sortir",row['class'])))
os.mkdir(os.path.join("Sortir",row['class']))
shutil.move(os.path.join("images",row["filename"]), os.path.join("Sortir",row['class']))

有人知道如何先读取行，然后移动文件吗？或者即使我想移动的文件已经被移动，也可以继续读取另一行？

在此处找到答案代码：

import shutil
import os
import pandas as pd
data = pd.read_csv('test.csv')
filenames = data['filename'].values
filenames = filenames.tolist()
classes = data['class'].values
classes = classes.tolist()
print(filenames)
print(classes)
for index, row in data.iterrows():
if not os.path.exists(os.path.join("SortirTest",row['class'])):
print("[INFO] 'creating {}' directory".format(os.path.join("SortirTest",row['class'])))
os.mkdir(os.path.join("SortirTest",row['class']))
input_name  = os.path.join("images", row["filename"])
output_name = os.path.join("SortirTest", row['class'], row['filename'])
if os.path.exists(input_name):
dest = shutil.move(input_name, output_name)
print("This File Has Been Moved:", input_name)
else:
print("This File Doesnt Exist :", input_name)
continue

Answer 1

在shutil.move()函数中，您也必须在新目录中添加文件名：

input_name  = os.path.join("images", row["filename"])
output_name = os.path.join("Sortir", row['class'], row['filename'])
shutil.move(input_name, output_name)

Answer 2

在运行脚本之前，您是否尝试过清除"Sortir"文件夹？