SELECT T.column_11,
count(column_11) count
FROM wp_tablesome_table_4695 T
JOIN wp_fea_submissions S ON T.column_2 = S.title
group BY T.column_11
wp_tablesome_table_4695
column 2 | column 11
1 | location 1
2 | location 2
3 | Location 3
wp_fea_submissions
title
1
1
2
3
结果
column 11| count
1 | 2
2 | 1
3 | 1
计数结果也是对重复的S进行计数。标题如何防止对重复进行计数
计数需要在子查询中完成。
SELECT T.column11,
count(column11) count
FROM wp_tablesome_table_4695 T
INNER JOIN (select distinct title
from wp_fea_submissions
) S ON T.column2 = S.title
group BY T.column11;
或
with cte as ( select distinct title
from wp_fea_submissions
) select wp.column11, count(wp.column11) as cnt
from cte
inner join wp_tablesome_table_4695 wp on wp.column2=cte.title
group by wp.column11;
https://dbfiddle.uk/iVprcr8z