所以我试图构建一个自动完成搜索栏,以按名称或id进行筛选,数据是从带有几个pokemon的JSON(data.JSON(中提取的。
以下是JSON:的一部分
{
"1" :{"id": "1", "name": "bulbasaur"},
"2" :{"id": "2", "name": "ivysaur"},
"3" :{"id": "3", "name": "venusaur"},
"4" :{"id": "4", "name": "charmander"},
"5" :{"id": "5", "name": "charmeleon"}
}
这是JS代码:
const search = document.querySelector('#search-bar');
const searchPokemon = async searchText => {
const res = await fetch('./data.json')
const pokemons = await res.json();
// Get matches
let matches = pokemons.filter(pokemon => {
const regexp = new RegExp(`^${searchText}`, 'gi');
return pokemon.name.match(regexp) || pokemon.id.match(regexp);
});
console.log(matches);
}
search.addEventListener('input', () => searchPokemon(search.value));
我想在控制台上获取匹配项,但我收到了一个未处理的Promise Rejection错误。我试过了。。。接球,但我还是有失误。有谁能为我指明正确的方向吗?谢谢
不要将console.log
效果放在search
函数中,而是将return
值放在中
async function searchPokemon(searchText) {
const res = await fetch('./data.json')
const pokemons = await res.json()
const regexp = new RegExp(`^${searchText}`, 'gi')
if (pokemons == null)
return []
else
return pokemons.filter(pokemon =>
pokemon.name.match(regexp) || pokemon.id.match(regexp)
)
}
将效果放在事件侦听器中。console.log
或searchResultElement.appendChild(...)
-
const search = document.querySelector('#search-bar');
search.addEventListener('input', async event => {
try {
const pokemons = await searchPokemon(search.value)
console.log("got pokemons", pokemons)
}
catch (err) {
console.error("An error occurred", err)
}
})