我需要序列化以下json
{
"searchText": "masktl_TABLE_GetMissingTables",
"$skip": 0,
"$top": 1,
"includeFacets": true
}
我试过这个
string payload = JsonConvert.SerializeObject(new
{
searchText = "masktl_TABLE_GetMissingTables",
$skip = 0,
$top = 1,
includeFacets = true
});
但是我们不能把$放在变量的名称中。有人能给我推荐其他序列化json的方法吗?
改为创建Dictionary<string, object>
:
var dictionary = new Dictionary<string, object>
{
["searchText"] = "masktl_TABLE_GetMissingTables",
["$skip"] = 0,
["$top"] = 1,
["includeFacets"] = true
};
string payload = JsonConvert.SerializeObject(dictionary);
或者,如果您需要从多个地方执行此操作,请创建一个具有相关属性的类,并使用JsonProperty
属性在JSON中指定名称。
例如:
public class SearchRequest
{
[JsonProperty("searchText")]
public string SearchText { get; set; }
[JsonProperty("$skip")]
public int Skip { get; set; }
[JsonProperty("$top")]
public int Top { get; set; }
[JsonProperty("includeFacets")]
public bool IncludeFacets { get; set; }
}
var request = new SearchRequest
{
SearchText = "masktl_TABLE_GetMissingTables",
Skip = 0,
Top = 1,
IncludeFacets = true
};
string payload = JsonConvert.SerializeObject(request);
您是否尝试过使用字典、而不是匿名对象
string payload = JsonConvert.SerializeObject(new Dictionary<string, object>()
{
{ "searchText", "masktl_TABLE_GetMissingTables" },
{ "$skip", 0 },
{ "$top", 1 },
{ "includeFacets", true }
});
尝试在线
如果您为给定的json格式定义了任何模型类,那么您可以JsonPropertyAttribute
在序列化时更改属性的名称。
声明:
public class Pagination
{
[JsonProperty("searchText")]
public string SearchText{ get; set; }
[JsonProperty("$skip")]
public int Skip { get; set; }
[JsonProperty("$top")]
public int Top { get; set; }
[JsonProperty("includeFacets")]
public bool IncludeFacets { get; set; }
}
用法:
var paginationObj = new Pagination()
{
SearchText = "masktl_TABLE_GetMissingTables",
Skip = 0,
Top = 1,
IncludeFacets = true
};
string payload = JsonConvert.SerializeObject(paginationObj);
尝试在线