我想做一个查询,给出与下面所示相同的结果,但我只需要在SET语句中插入前4位数字,即" SET $campaign = '0029'"有没有办法在这样的字符串语句中填充通配符?
declare @campaignNo varchar(60)
set @campaignNo = '0029_old_Leu_2021_1'
Select Count(PUR1.intTimestamp) AS #start
From [MicrobialScreening].[dbo].[PUR_IDs] as ID
INNER JOIN [MicrobialScreening].[dbo].[PUR_Purification1] AS PUR1
ON id.intID=pur1.intID
where id.strCampaign = @campaignNo
也许LIKE是你想要的:
declare @campaignNo varchar(60)
set @campaignNo = '0029'
Select Count(PUR1.intTimestamp) AS #start
From [MicrobialScreening].[dbo].[PUR_IDs] as ID
INNER JOIN [MicrobialScreening].[dbo].[PUR_Purification1] AS PUR1
ON id.intID=pur1.intID
where id.strCampaign like @campaignNo+'%'
如果活动号是固定宽度的(如最初问题中所述的前四个),您可以使用LEFT函数。
set @campaignNo = '0029'
…
where LEFT(id.strCampaign, 4) = @campaignNo
对于更复杂的解析,可以使用SUBSTRING或LIKE。如果您使用下划线来使用LIKE进行解析,请确保使用ESCAPE关键字来避免歧义。
where id.strCampaign = LIKE CONCAT(@campaignNo, '_%') ESCAPE ''