TicTacToe Java check for draw

Question

在我的《TicTacToe》游戏中，我有一个检查是否有人获胜的方法，这个方法非常有效。但是检查是否有平局的方法不起作用。首先，它会检查是否有赢家，如果没有，它会检查是否有平局。一旦场上每9个位置都有比赛，就会出现"平局"的消息。不出现。我找不到错误。

for (int i = 0; i < 5; i++) {
System.out.println("welcome!");
playerMove(gameBoard);
if (checkIfCurrentPlayerIsWinner(gameBoard, 'X')) {
System.out.println("Player won the game!");
playerScore++;
break;
if (checkDraw(gameBoard)) {
System.out.println("It's a draw!");
tieScore++;
break;
}
private static boolean checkDraw(char[][] gameBoard){
for(int i = 1; i< 10; i++){
if(getFieldContent(gameBoard, i) != ' '){
return false;
}
}
return true;
}
public static char getFieldContent(char[][] gameboard, int fieldNumber) {
switch (fieldNumber) {
case 1:
return gameboard[0][0];
case 2:
return gameboard[0][2];
case 3:
return gameboard[0][4];
case 4:
return gameboard[2][0];
case 5:
return gameboard[2][2];
case 6:
return gameboard[2][4];
case 7:
return gameboard[4][0];
case 8:
return gameboard[4][2];
case 9:
return gameboard[4][4];
}
return ' ';
}

Answer 1

我在这里推断gameboard最初包含所有空格，并且由于某种原因您决定仅在其偶数索引中存储移动。我还会注意到你的代码缺少一些闭括号(}s)。请在将来只发送编译代码，或者如果编译是你的问题，请注明。

在任何情况下，如果gameboard中所有测试的索引不是' '和true，则checkDraw返回false。似乎你想要测试的是相反的，即整个棋盘已经播放，即没有非空格细胞存在。在这种情况下，checkDraw看起来像下面这样:

private static boolean checkDraw(char[][] gameBoard) {
for(int i = 1; i < 10; i++) {
// note that the test is now == instead of !=
if(getFieldContent(gameBoard, i) == ' ') {
return false;
}
}
// no non-space cells were found, so the entire board has been
// played out, resulting in a draw, provided that a separate
// winner check has already been conducted
return true;
}