隐藏PyQt主窗口会影响子对话框的行为

Question

在PyQt5中，我想知道为什么隐藏QMainWindow会影响子对话框的行为?

例如，在下面的代码中，如果我点击"显示对话框"→"ok"，显示QMessageBox，然后程序终止。但是，如果我注释掉showChildDialog()中的self.hide()和self.show()，程序将在显示QMessageBox之后返回显示子对话框。

理想情况下，我希望程序在显示QMessageBox后返回到子对话框，但我也希望在显示子对话框时隐藏主窗口。

如何同时实现这两种行为?

from PyQt5 import QtWidgets

class mainWindow(QtWidgets.QMainWindow):
def __init__(self, parent=None):
super(mainWindow, self).__init__(parent)
self.dialog = childDialog(self)
self.setWindowTitle('Main Window')
self.buttonShow = QtWidgets.QPushButton(self)
self.buttonShow.setText("Show Dialog")
self.buttonShow.clicked.connect(self.showChildDialog)
def showChildDialog(self):
self.hide()                 # works as intended if this commented out...
self.dialog.exec()
self.show()                 # and this.

class childDialog(QtWidgets.QDialog):
def __init__(self, parent=None):
super(childDialog, self).__init__(parent)
self.buttonOk = QtWidgets.QPushButton(self)
self.buttonOk.setText("OK")
self.buttonOk.clicked.connect(self.ok_clicked)
self.buttonHide = QtWidgets.QPushButton(self)
self.buttonHide.setText("Close")
self.buttonHide.clicked.connect(self.hide_clicked)
self.layout = QtWidgets.QVBoxLayout(self)
self.layout.addWidget(self.buttonOk)
self.layout.addWidget(self.buttonHide)
def hide_clicked(self):
self.accept()
def ok_clicked(self):
# do somehting here that causes an error
dialog = QtWidgets.QMessageBox(text='an error occurred')
dialog.exec()

if __name__ == "__main__":
import sys
app = QtWidgets.QApplication(sys.argv)
app.setApplicationName('myWindow')
main = mainWindow()
main.show()
sys.exit(app.exec_())

Answer 1

如果你改变这一行:

self.dialog = childDialog(self)

到这行:

self.dialog = childDialog()

工作正常