Python遍历存储在变量中的每个单独列表，并将其作为单个列表

Question

我在变量中存储了列表x = ['eventVersion', '1.08'] ['userIdentity', {'type': 'IAMUser', 'principalId': '', 'accountId': '', 'accessKeyId': '', 'userName': 'test'}] ['eventTime', '2021-09-22T13:49:49Z'] ['eventSource', 'signin.amazonaws.com']

我试图将其转换为单个列表，我试图通过列表循环，但只提供'eventVersion'， '1.08'。如何循环遍历每个子列表并获得所有信息?

感谢您的帮助

Answer 1

假设这是输入和注释中提供的预期输出，则需要字典将其转换为键:值对格式，不能使用列表。

x = [
['eventVersion', '1.08'], 
[{'userIdentity': 
{
'type': 'IAMUser', 
'principalId': '', 
'accountId': '', 
'accessKeyId': '', 
'userName': 'test'
}
}], 
['eventTime', '2021-09-22T13:49:49Z'], 
['eventSource', 'signin.amazonaws.com'], 
['eventName', 'ConsoleLogin'], 
['awsRegion', 'us-east-1'], 
['sourceIPAddress', '.'], 
['userAgent', 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/93.0.4577.82 Safari/537.36'], 
['errorMessage', 'Failed authentication'], 
['requestParameters', None],
[{"responseElements":{"ConsoleLogin":"Success"}}],
[{"additionalEventData" : ""}]
]
converted = {}
for item in x:
if isinstance(item[0], dict):
converted.update(item[0])
continue
converted[item[0]] = item[1]
for k,v in converted.items():
print(k," : ",v)

给输出

eventVersion  :  1.08
userIdentity  :  {'type': 'IAMUser', 'principalId': '', 'accountId': '', 'accessKeyId': '', 'userName': 'test'}
eventTime  :  2021-09-22T13:49:49Z
eventSource  :  signin.amazonaws.com
eventName  :  ConsoleLogin
awsRegion  :  us-east-1
sourceIPAddress  :  .
userAgent  :  Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/93.0.4577.82 Safari/537.36
errorMessage  :  Failed authentication
requestParameters  :  None
responseElements  :  {'ConsoleLogin': 'Success'}
additionalEventData  :