PHP删除特定字符(文件扩展名)之后的任何内容

Question

我想删除一组特定字符(即文件类型/扩展名(后面的任何内容。我试过很多我在网上找到的脚本，但没有一个能真正做到我需要的，它们要么也删除了文件扩展名，要么保留了后面的部分参数。

$urls = array(
'http://www.example.com/images/image1.jpg',
'http://www.example.com/images/image2.png?arg=value',
'http://www.example.com/images/image3.jpg?foo=bar',
'http://www.example.com/images/image4.gif?v=1',
'http://www.example.com/images/image5.bmp?x=y',
'http://www.example.com/images/image6.tiff?werdfs=234234'
);

期望结果：

http://www.example.com/images/image1.jpg
http://www.example.com/images/image2.png
http://www.example.com/images/image3.jpg
http://www.example.com/images/image4.gif
http://www.example.com/images/image5.bmp
http://www.example.com/images/image6.tiff

Answer 1

也许这个对你有帮助。

$re = '/^.*(?:.)[a-zA-Z]+/m';
$urls = array(
'http://www.example.com/images/image1.jpg',
'http://www.example.com/images/image2.png?arg=value',
'http://www.example.com/images/image3.jpg?foo=bar',
'http://www.example.com/images/image4.gif?v=1',
'http://www.example.com/images/image5.bmp?x=y',
'http://www.example.com/images/image6.tiff?werdfs=234234',
'asdasd'
);
foreach ($urls as $url) {
preg_match($re, $url, $matches);
if ($matches) {
echo $matches[0];
echo "n";
}
}

输出

http://www.example.com/images/image1.jpg
http://www.example.com/images/image2.png
http://www.example.com/images/image3.jpg
http://www.example.com/images/image4.gif
http://www.example.com/images/image5.bmp
http://www.example.com/images/image6.tiff

Answer 2

PHP的parse_url((和basename怎么样？

$inName = $urls[0]; // for example
$newName = parse_url($inName,PHP_URL_SCHEME)
. parse_url($inName,PHP_URL_HOST)
. parse_url($inName,PHP_URL_PATH)
. basename($inName);