根据得分值将敌人添加到游戏中

Question

我是一个初学者，需要很多帮助才能走到这一步。当我的分数达到10、20等特定值时，我试图添加更多的敌人。我尝试了一些类似if score_value>=的方法10:num_of_enemies = num_of_enemies + 10，但一直未能产生结果。我觉得它应该很简单，但我错过了如何在这个列表中添加值。

import pygame
import random
import math
from pygame import mixer
# initialize game
pygame.init()
# create screen, set height and weight (())
screen = pygame.display.set_mode((800, 600))
# Background
background = pygame.image.load('background1.png')
pygame.display.set_icon(background)
# Background sound
mixer.music.load('troubador.wav')
mixer.music.play(-1)
# Title and Icon
pygame.display.set_caption("Beasts of Cthulu")
icon = pygame.image.load('knight.png')
pygame.display.set_icon(icon)
# Player
playerImg = pygame.image.load('wizard.png')
playerX = 370
playerY = 500
playerX_change = 0
# Enemy
enemyImg = []
enemyX = []
enemyY = []
enemyX_change = []
enemyY_change = []
num_of_enemies = 5
max_enemies = 100
for i in range(num_of_enemies):
enemyImg.append(pygame.image.load('cthulhu.png'))
enemyX.append(random.randint(0, 735))
enemyY.append(random.randint(10, 150))
enemyX_change.append(3)
enemyY_change.append(40)
# Fireball
# ready - you cannot see fireball on screen
# fire - fireball is currently moving
fireballImg = pygame.image.load('fireball.png')
fireballX = 0
fireballY = 370
fireballX_change = 0
fireballY_change = 8
fireball_state = "ready"
# Score
score_value = 0
previous_score = score_value
font = pygame.font.Font('Enchanted_Land.otf', 32)
textX = 10
textY = 10
# Game over text
over_font = pygame.font.Font('Enchanted_Land.otf', 64)

def show_score(x, y):
score = font.render("Score :" + str(score_value), True, (255, 255, 255))
screen.blit(score, (x, y))

def game_over_text():
over_text = over_font.render("GAME OVER", True, (255, 255, 255))
screen.blit(over_text, (250, 200))

def player(x, y):
screen.blit(playerImg, (x, y))

def enemy(x, y, i):
screen.blit(enemyImg[i], (x, y))

def fire_fireball(x, y):
global fireball_state
fireball_state = "fire"
screen.blit(fireballImg, (x + 16, y + 10))

def isCollision(enemyX, enemyY, fireballX, fireballY):
distance = math.sqrt(math.pow(enemyX - fireballX, 2) + (math.pow(enemyY - fireballY, 2)))
if distance < 27:
return True
else:
return False
# Game Loop

running = True
while running:
screen.fill((0, 0, 0))
# Background image
screen.blit(background, (0, 0))
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
# Keyboard actions
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_LEFT:
playerX_change = -4
if event.key == pygame.K_RIGHT:
playerX_change = 4
if event.key == pygame.K_SPACE:
if fireball_state == "ready":
fireball_Sound = mixer.Sound('fireball-1.wav')
fireball_Sound.play()
fireballX = playerX
fire_fireball(fireballX, fireballY)
if event.type == pygame.KEYUP:
if event.key == pygame.K_LEFT or event.key == pygame.K_RIGHT:
playerX_change = 0
# checking for boundaries
playerX += playerX_change
if playerX <= 0:
playerX = 0
elif playerX >= 736:
playerX = 736
# Fireball movement
if fireballY <= 0:
fireballY = 480
fireball_state = "ready"
if fireball_state == "fire":
fire_fireball(fireballX, fireballY)
fireballY -= fireballY_change

# Enemy movement
enemyX += enemyX_change
for i in range(num_of_enemies):
# Game Over
if enemyY[1] > 370:
for j in range(num_of_enemies):
enemyY[j] = 2000
game_over_text()
break
enemyX[i] += enemyX_change[i]
if enemyX[i] <= 0:
enemyX_change[i] = 3
enemyY[i] += enemyY_change[i]
elif enemyX[i] >= 736:
enemyX_change[i] = -3
enemyY[i] += enemyY_change[i]

# Collision
collision = isCollision(enemyX[i], enemyY[i], fireballX, fireballY)
if collision:
explosion_Sound = mixer.Sound('fireball-explosion.wav')
explosion_Sound.play()
fireballY = 480
fireball_state = "ready"
score_value += 1
enemyX[i] = random.randint(0, 735)
enemyY[i] = random.randint(10, 150)
enemy(enemyX[i], enemyY[i], i)


player(playerX, playerY)
show_score(textX, textY)
pygame.display.update()

Answer 1

这是大量的代码，我们无法运行它，因为我们没有资产。你需要的是一个阈值，一旦达到这个阈值就会增加。

你可以这样实现：

import random
threshold = 10
score = 0
while score < 1000:
score += random.randint(1,4)  # wherever points come from
print (f"Score {score}")
if score > threshold:
print (f"You have more than {threshold}. Adding enemies ...")
threshold += 10

看看分数是如何增加的，但敌人只会每10分增加一次，而且不需要精确命中数值。

Answer 2

@ThomasWeller的想法很好(+1(。但是，将它添加到代码中会遇到困难。

编写一个添加敌人的函数，并在创建初始敌人的循环中使用该函数：

enemySurf = pygame.image.load('cthulhu.png')
def addNewEnemy():
enemyImg.append(enemySurf)
enemyX.append(random.randint(0, 735))
enemyY.append(random.randint(10, 150))
enemyX_change.append(3)
enemyY_change.append(40)
for i in range(num_of_enemies):
addNewEnemy()

使用@ThomasWeller的想法，当踏板车达到一定阈值时添加一个新敌人：

threshold = 10
running = True
while running:
if score_value >= threshold:
addNewEnemy()
num_of_enemies += 1
threshold += 10
print(len(enemyX))
# [...]