Promise Map一直返回null

Question

我已经做了24个多小时了，一切似乎都如我所愿，但承诺一直返回null。

[
null,
null
]

这是我的代码：

let vettedBatch = currentBatch.Items.map((current) => {
getUser(current.userId).then((res) => {
// return resolve(JSON.parse(res.body));
let body = JSON.parse(res.body);
if (body.hasOwnProperty("Item")) {
return body;
} else {
//if user does not exist on the users table based on ID, lets take his transaction out of the fail-safe table
console.log(
`user with id number ${current.userId} with transaction id ${current.txId} do not exist or must have been disabled`
);
User.deleteWithdrawalTx(current.txId).then(() => {
console.log(
`transaction id ${current.txId} delete for unknown user with userId ${current.userId}`
);
});
}
});
});

Answer 1

您需要使用Promise.all:

const data = [];
const promises = currentBatch.Items.map(async current => {
return await getUser(current.userId)
});
Promise.all(promises)
.then(res => {
res.map(item => {
let { body } = JSON.parse(item);
if (body.hasOwnProperty("Item")) {
data.push(body);
} else {
console.log('message');
}
})
})

Answer 2

我建议您不要混合使用async/await和Promise语法。

以下是完全用async/await语法编写的代码：

const getData = async () => { // async function instead of new Promise()...
return Promise.all(currentBatch.Items.map(async (current) => { // make map async and await it with Promise.all()
const res = await getUser(current.userId); // await instead of .then()
let body = JSON.parse(res.body);
if (body.hasOwnProperty("Item")) {
return body;
} else {
console.log(`user with id number ${current.userId} with transaction id ${current.txId} do not exist or must have been disabled`);
await User.deleteWithdrawalTx(current.txId); // await instead of .then()
console.log(`transaction id ${current.txId} delete for unknown user with userId ${current.userId}`);
// You should return something here too, but I dont know what you want to return, so...
}
}));
}
let vettedBatch = await getData(); // await the async function

您的问题实际上偏离了这个问题：如何从异步调用返回响应？。在我的回答中应该是固定的，但我仍然建议你查看链接的线程。