在C中打印uint64_t*值

Question

我正在使用以下代码：

size_t offset = (rand() << 12) % chunk_size;
uint64_t *addr = (uint64_t*) (chunk+offset);
fprintf(stdout,"addr: %" PRIx64 " ", addr);

我包含了<inttypes.h>库，但我得到了以下错误：

error: format ‘%lx’ expects argument of type ‘long unsigned int’, but argument 3 has type ‘uint64_t *’ {aka ‘long unsigned int *’} [-Werror=format=]
fprintf(stdout,"addr: %" PRIx64 " ", addr);  
uint64_t * {aka long unsigned int *}
In file included from filename.c:5:
/usr/include/inttypes.h:121:34: note: format string is defined here
121 | # define PRIx64  __PRI64_PREFIX "x"
cc1: all warnings being treated as errors
make: *** [Makefile:8: filename.o] Error 1

为什么？

谢谢。

Answer 1

问题是要打印的类型是uint64_t *而不是uint64_t，因此，如果要打印指针(addr(，只需在printf中使用%p，否则需要使用*取消引用指针。