为什么运行firebase模拟器也执行我的一个函数

Question

我运行firebase emulators:start --only functions,firestore并获得以下输出：

$ firebase emulators:start  --only functions,firestore
i  emulators: Starting emulators: functions, firestore
⚠  functions: The following emulators are not running, calls to these services from the Functions emulator will affect production: database, hosting, pubsub
✔  functions: Using node@10 from host.
⚠  functions: Your GOOGLE_APPLICATION_CREDENTIALS environment variable points to /Users/user/development/project/app/serviceKey.json. Non-emulated services will access production using these credentials. Be careful!
i  firestore: Firestore Emulator logging to firestore-debug.log
i  ui: Emulator UI logging to ui-debug.log
i  functions: Watching "/Users/user/development/project/app/functions" for Cloud Functions...
>  TEST TEST 123
✔  functions[test-func1]: http function initialized (http://localhost:5001/project-9999d/us-east1/test-func1).
✔  functions[test-func2]: http function initialized (http://localhost:5001/project-9999d/us-east1/test-func2).
✔  functions[test-func3]: firestore function initialized.
✔  functions[test1-func1]: http function initialized (http://localhost:5001/project-9999d/us-east1/test1-func1).
✔  functions[test1-func2]: http function initialized (http://localhost:5001/project-9999d/us-east1/test1-func2).
✔  functions[test3-func1]: http function initialized (http://localhost:5001/project-9999d/us-east1/test3-func1).
✔  functions[test3-func2]: http function initialized (http://localhost:5001/project-9999d/us-east1/test3-func2).
✔  functions[test4]: http function initialized (http://localhost:5001/project-9999d/us-east1/test4).
i  functions[test5-func1]: function ignored because the pubsub emulator does not exist or is not running.

函数在functions/scraper/index.js中定义为：

exports.scraper = url => {
console.log('TEST TEST', url)
return null
}

在functions/cron/index.js中导入并调用

const functions = require('firebase-functions')
const test = require('../scraper')
const schedule = `every 6 hours`
exports.testFunction = functions.pubsub
.schedule(schedule)
.onRun(test.scraper('123'))

为什么我看到这个函数的TEST TEST 123输出，而没有看到其他函数的输出？运行模拟器时，如何避免执行此函数？

我试图在本地测试一个调度的cron函数，但它在运行模拟器时一直在执行。

Answer 1

通过编写.onRun(test.scraper('123'))，您要求pubsub运行test.scraper('123')的返回值。这就是在环境初始化期间调用该函数的原因。

如果你想每6小时运行一次test.scraper('123')，你必须把它包装成一个函数。

exports.testFunction = functions.pubsub
.schedule(schedule)
.onRun(() => test.scraper('123'))

更清楚的是：

exports.testFunction = functions.pubsub
.schedule(schedule)
.onRun(scheduledFunction)
function scheduledFunction() {
test.scraper('123')
}