使用由布尔函数Python组成的列表创建OR逻辑函数

Question

我想写一个函数，检查Trueboolena语句是否在all_vals内。如果有True值，则代码将为yes。如果没有，则代码输出no，本质上创建一个或语句。下面的代码不起作用。我该如何修改它，使其获得下面的预期输出？

def vals(all_vals):
for x in all_vals:
if True in all_vals:
print('yes')
else:
print('no')

a = [True, True, True]
b = [True, False, True, True, False]
c = [False, False]
d = [True, False]
vals([a,b,c,d]) 

预期输出：

yes
yes
no
yes

Answer 1

您需要的不是：if True in all_vals:而是if True in x:，如下所示：

def vals(all_vals):
for x in all_vals:
if True in x:
print('yes')
else:
print('no')

a = [True, True, True]
b = [True, False, True, True, False]
c = [False, False]
d = [True, False]
vals([a,b,c,d]) 

此外，您还可以使用来持久地缩短代码

vals = lambda all_vals: print("n".join(['yes' if True in i else 'no' for i in all_vals]))
a = [True, True, True]
b = [True, False, True, True, False]
c = [False, False]
d = [True, False]
vals([a,b,c,d]) 

输出：

yes
yes
no
yes

Answer 2

def vals(all_vals):
for x in all_vals:
if True in x: # <--- Your typo here
print("yes")
else:
print("no")

a = [True, True, True]
b = [True, False, True, True, False]
c = [False, False]
d = [True, False]
vals([a, b, c, d])