如何在异常超时后重试，并从dict中删除

Question

我想增加抓取内容的覆盖率，避免超时，但我希望如果页面出现超时错误，然后重试，但如果第二轮超时增加了超时计数器，则重试URL，最多重试3次，如果没有增加从dict 中删除

async def _worker(self, i):
while True:
url = await self.fetching.get()
if url is None:
return
#logger.info(f'Fetch worker {i} is fetching a URL: {url}')
try:
site = await self._fetch_rss(url)
await self._processing(site)
except asyncio.TimeoutError as err:
while self.timeouts[url] < 1:
logger.info("adding {}".format(url))
site = await self.fetch(url)
await self.process(site)
self.timeouts[url] += 1

Answer 1

通常；尝试n次，如果我从未成功，就会犯错"；如下所示：

for _ in range(MAX_TRIES):
try:
# do something
pass
except Exception:
# handle exception
pass
else:
break
else: # A lesser-known syntax; else after for is only run if the for *wasn't* broken out of
# We never broke, which means we never had a success, so handle the failure here
pass