relativelta函数的python动态值

Question

Im试图为relativelta函数提供动态值，即relativedelta(days=1)我想将动态函数值days、months、years分配给该函数。考虑我的情况如下。我将得到列表动态如下：

Ex: 1
list = ['today', 'minus', '1', 'days']
Ex: 2
list = ['today', 'plus', '1', 'year']
Ex: 3
list = ['today', 'plus', '1', 'months']

我写代码来处理的计算

import operator
from datetime import datetime
from datetime import date
from dateutil.relativedelta import relativedelta
operations = {
'plus': operator.add,
'minus': operator.sub,
}
today = date.today()
new_date = self.operations['plus'](today, relativedelta(days=1))
# the above is some thing like [today + relativedelta(days=1)]

我想做的是像operations一样。我想把days、months、years分配给relativedelta()函数，但我做不到。有什么建议的方法吗？

Answer 1

找到了一种方法！

我们可以使用**expression调用语法将字典传递给函数，相反，它将被扩展为关键字参数(**kwargs函数参数将再次捕获(：

attributes = {'days': 1}
relativedelta(**attributes)