如何检查ON DUPLICATE语句中更新和插入了多少行

Question

我有一个语句如下：

$count=0;
while($row = pg_fetch_assoc($result)){
$sql=("INSERT INTO joblist (job_no, billed, completed, paid, paid_amount, inv_no, invoice, type, o_submitted, approval_date, gals, jobtype, name, state, region, territory) 
VALUES (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?) ON DUPLICATE KEY UPDATE
job_no=VALUES(job_no), billed=VALUES(billed),completed=VALUES(completed), paid=VALUES(paid), paid_amount=VALUES(paid_amount), inv_no=VALUES(inv_no), invoice=VALUES(invoice), type=VALUES(type), o_submitted=VALUES(o_submitted), approval_date=VALUES(approval_date), gals=VALUES(gals), jobtype=VALUES(jobtype), name=VALUES(name), state=VALUES(state), region=VALUES(region), territory=VALUES(territory)");
$stmt = $conn->prepare($sql);
$stmt->bind_param("ssssssssssssssss",$job_no, $billed, $completed, $paid, $paid_amount, $inv_no, $invoice, $type, $o_submitted, $approval_date, $gals, $jobtype, $name, $state, $region, $territory);
$stmt->execute();
$count++;
}

问题是，我无法区分更新的行和插入的行。有什么办法我能做到这一点吗？我知道我可以使用effected rows函数，但如果更新/插入，它的读数是一样的。有什么想法吗？谢谢

Answer 1

您正在寻找一个带有RETURNING子句的UPSERT。

考虑到下表a的记录。。

CREATE TEMPORARY TABLE t 
(id INT PRIMARY KEY, name TEXT);
INSERT INTO t VALUES (1,'elgar'),(2,'bach'),(3,'brahms');

可以使用UPSERT捕获主键冲突，并要求查询返回受影响的记录。您可以将此插入放入CTE中，并使用新查询对其进行计数。以下查询将插入两个已存在的主键(1和2(和一个新主键(4(：

WITH j (affected_rows) AS (
INSERT INTO t VALUES (1,'edward'),(2,'johann sebastian'),(4,'schubert')
ON CONFLICT (id) DO UPDATE SET name = EXCLUDED.name
RETURNING *
) SELECT count(affected_rows) FROM j;
count 
-------
3

自己看看结果：-(

SELECT * FROM t ORDER BY id;
id |       name       
----+------------------
1 | edward
2 | johann sebastian
3 | brahms
4 | telemann