我正在尝试覆盖doGet和doPost，并尝试调用doPost，但无法工作。以下是JSP和Servlet代码
<%@ page language="java" %>
<!DOCTYPE html>
<html>
<head>
<title>Insert title here</title>
</head>
<body>
<form method="post" action="FirstServlet">
<input type="text" name="Name" value="Enter">
<input type="button" name="submit" value="Submit"/>
</form>
</body>
</html>
Servlet代码在下面，试图调用doPost方法，但它没有被调用，也没有在控制台中打印消息。然而，当我尝试直接从URL访问servlet时，它的doGet方法被称为
import java.io.IOException;
import javax.servlet.ServletConfig;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* Servlet implementation class FirstServlet
*/
@WebServlet("/FirstServlet")
public class FirstServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
/**
* @see HttpServlet#HttpServlet()
*/
public FirstServlet() {
super();
System.out.println(" Inside Constructor");
// TODO Auto-generated constructor stub
}
/**
* @see Servlet#init(ServletConfig)
*/
public void init(ServletConfig config) throws ServletException {
// TODO Auto-generated method stub
System.out.println(" Inside init");
}
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
System.out.println(" Inside doGet");
response.getWriter().append("Served at: ").append(request.getContextPath());
}
/**
* @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
*/
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
System.out.println(" Inside doPost");
doGet(request, response);
}
}
您的HTML表单提交按钮不正确：修复type属性。尝试：
<input type="submit" name="submit" value="Submit"/>