PyGame:对位于两个列表中的几个图像使用img.get_rect()，并为它们使用唯一的宽度和高度变量

Question

我开始用Python中的PyGame创建一个新游戏，我把我的精灵的所有图像都放在两个列表中，所以当我用箭头移动精灵时，它会读取包含精灵图像的列表，它会产生真实效果(因为我们会看到精灵的腿在移动(。问题是显然我们不能对两个列表中的图像使用self.rect.x和self.rect.y|错误：AttributeError: 'list' object has no attribute 'x'

这是我的代码：

文件：main.py

import os
from player import Player
import pygame
pygame.init()
current_path = os.path.dirname(__file__)
image_path = os.path.join(current_path, 'images')
screen = pygame.display.set_mode((1280,720))
pygame.display.set_caption("Shoot The Villains")
persoDroit = pygame.image.load(os.path.join(image_path, 'Sprite_soldatDroitSansFeu.png'))
enemyRight = pygame.image.load(os.path.join(image_path, 'Sprite_ennemiDroit.png'))
enemyLeft = pygame.image.load(os.path.join(image_path, 'Sprite_ennemiGauche.png'))
backgroundGame = pygame.image.load(os.path.join(image_path, 'background.png'))
def affichage(health_Player, health_Enemy):
global countSteps
if player.countSteps >= 4: 
player.countSteps = 0 
if left:
screen.blit(player.go_left[player.countSteps], player.rect.x) #Here I tried to call rect.x, in __init__ and move_left function, it doesn't work
player.countSteps += 1 
elif right:
screen.blit(player.go_right[player.countSteps], (player.x,player.y))
player.countSteps += 1
else:
screen.blit(persoDroit, (player.x,player.y))
player = Player()
palying = True 
while playing:
screen.blit(backgroundGame, [0,0])
for event in pygame.event.get():
touche = pygame.key.get_pressed()
if event.type == pygame.QUIT or touche[pygame.K_ESCAPE]:
playing = False
if touche[pygame.K_LEFT] and player.rect.x > 0:
left = True
right = False
player.move_left() #I tried to call the function move_left in the Player() class
elif touche[pygame.K_RIGHT] and player.x < screen.get_width()-64:
left = False
right = True
player.x += player.speed
else:
left = False
right = False
player.countSteps = 0
display(player.health_Player, health_Enemy)
pygame.display.update()
pygame.quit()

第二个文件：player.py

import os
import pygame
current_path = os.path.dirname(__file__)
image_path = os.path.join(current_path, 'images')
class Player (pygame.sprite.Sprite):
def __init__(self):
super().__init__() # On initialise 'pygame.sprite.Sprite'
self.health_Player = 100
self.reamaning_health_Player = self.health_Player / (20/13)
self.attackDMG = 10
self.speed = 7.5
self.jumpCount = self.speed
self.countSteps = 0
self.go_left = [pygame.image.load(os.path.join(image_path, 'Sprite_soldatGauche1-4.png')),pygame.image.load(os.path.join(image_path, 'Sprite_soldatGauche2-4.png')),pygame.image.load(os.path.join(image_path, 'Sprite_soldatGauche3-4.png')), pygame.image.load(os.path.join(image_path, 'Sprite_soldatGauche4-4.png'))]
self.go_right = [pygame.image.load(os.path.join(image_path, 'Sprite_soldatDroit1-4.png')),pygame.image.load(os.path.join(image_path, 'Sprite_soldatDroit2-4.png')),pygame.image.load(os.path.join(image_path, 'Sprite_soldatDroit3-4.png')), pygame.image.load(os.path.join(image_path, 'Sprite_soldatDroit4-4.png'))]
self.rect = [img.get_rect() for img in self.go_left and self.go_right]
self.rect.x = 25 #The problem is here
self.rect.y = 640 #The problem is here
def move_left (self):
self.rect.x -= self.speed #The problem is here

问题出在第二个文件中，我用#那么，我能做些什么，将两个列表的每个图片定位在两个变量中：self.rect.x和self.rect.y？感谢您花时间回顾我的问题！

Answer 1

当您基于pygame.sprite.Sprite制作PyGameSprite时，子画面.image和.rect是定义子画面所在位置和外观的关键组件。

CCD_ 10是单个CCD_。

Sprite.rect是单个pygame.Rect

您的代码正在将Rect列表分配给Sprite.rect，这将不起作用。大多数sprite实现都会更改sprite.update()函数中的图像和矩形，该函数在每帧调用一次。

那么，如何前进。首先修复精灵矩形：

class Player( pygame.sprite.Sprite ):
LEFT  = 0       # enumerated direction types
RIGHT = 1
def __init__( self, image_path, x, y ):
pygame.sprite.Sprite.__init__( self )
# Load animation
self.go_left = [pygame.image.load(os.path.join(image_path, 'Sprite_soldatGauche1-4.png')),pygame.image.load(os.path.join(image_path, 'Sprite_soldatGauche2-4.png')),pygame.image.load(os.path.join(image_path, 'Sprite_soldatGauche3-4.png')), pygame.image.load(os.path.join(image_path, 'Sprite_soldatGauche4-4.png'))]
self.go_right = [pygame.image.load(os.path.join(image_path, 'Sprite_soldatDroit1-4.png')),pygame.image.load(os.path.join(image_path, 'Sprite_soldatDroit2-4.png')),pygame.image.load(os.path.join(image_path, 'Sprite_soldatDroit3-4.png')), pygame.image.load(os.path.join(image_path, 'Sprite_soldatDroit4-4.png'))]
self.image      = self.go_left[0]
self.rect       = self.image.get_rect()
self.rect.x     = x
self.rect.y     = y
self.direction  = self.LEFT  # initially heading left
self.frame_index= 0          # which animation frame is used

这将正确地将图像和矩形设置为第一个动画帧，假设玩家开始面向左侧。

然后，当玩家移动时，按正确的方向循环播放动画。这里的关键思想是，要使精灵动画化，代码只需为方向选择下一个图像，然后重新定位sprite.rect，以匹配图像和新位置。

def move( self, direction, x_delta ):
# use the next animation index
if ( direction != self.direction ):   # player turned?
self.frame_index = 0
else:
self.frame_index += 1             # player continued
self.direction = direction
if ( direction == Player.LEFT ):
# loop at the last frame
self.frame_index %= len( self.go_left )          
self.image = self.go_left[ self.frame_index ]
else:  # direction == Player.RIGHT
self.frame_index %= len( self.go_right )
self.image = self.go_right[ self.frame_index ]
# re-create the rect with the current co-ordinates
x, y = self.rect.center
self.rect = self.image.get_rect()
self.rect.center = ( x + x_delta, y )

在您当前的代码中，看起来您正试图维护一个rect列表。但你如何保持他们的立场更新？它不会为你节省任何东西，因为图像已经有了矩形。

此外，我只是猜测这就是你的动画应该如何工作，也许它是一个基于时间的动画。所以，这只是为了说明一种方法。也许它会给你一些帮助的想法。